The density of mercury is 13.5 g/cm3

What are the horizontal and vertical velocities of a stunt bike that leaves a ramp at 100 km/hr and at an angle of 35 degrees?

Alex787 [66]

Horizontal velocity: 81.9 km/h

Vertical velocity: 57.4 km/h

Explanation:

We can solve this problem by resolving the velocity vector into its component along the horizontal and vertical direction.

The horizontal velocity of the stunt bike is given by:

$v_x = v cos \theta$

where

v = 100 km/h is the magnitude of the velocity

$\theta=35^{\circ}$ is the angle of projection

Substituting, we find

$v_x = (100)(cos 35^{\circ})=81.9 km/h$

The vertical velocity instead is given by

$v_y = v sin \theta$

where

$v=100 km/h$

$\theta=35^{\circ}$

Substituting,

$v_y = (100)(sin 35^{\circ})=57.4 km/h$

Learn more about vector components:

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4 0

3 years ago

Find the velocity, acceleration, and speed of a particle with the given position function. r(t) = t i + t2 j + 3 k v(t) = a(t) =

stepladder [879]

Answer:

Velocity

v= i + 2 j

Acceleration

a= 2 j

Explanation:

Given that

r(t) = t i + t² j + 3 k

We know that

Velocity v given as

v= dr/dt

dr/dt= i + 2 t j +0

v= i + 2 t j

At t= 1

v= i + 2 x 1 j

v= i + 2 j

Acceleration ,a

a= dv/dt

v= i + 2 t j

dv/dt= 2 j

a= 2 j

6 0

3 years ago

If an investigator wanted to reproduce the results with a beam of protons, what would require to get a strong m = 1 reflection a

Elis [28]

When the investigator wanted to reproduce the results with a beam of protons, the thing required is A. Lower speed particles than for the electron beam.

<h3>What is proton?</h3>

It should be noted that a proton simply means a stable subatomic particle that has a positive electric charge.

In this case, when the investigator wanted to reproduce the results with a beam of protons, the thing required is a lower speed particles than for the electron beam.

Learn more about protons on:

brainly.com/question/1805828

3 0

3 years ago

A closed, rigid tank is filled with water. Initially, the tank holds 9.9 ft3 of saturated vapor and 0.1 ft3 of saturated liquid,

Galina-37 [17]

Answer:

a) x₁ = 0.058

b) T₂ = 416.02°F

c) q = 5047.39 Btu

Explanation:

see the attached file