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Oxana [17]
4 years ago
6

Albert observes that Emmy's watch is ticking eanwhile, Emmy observes Albert's watch and compares it with her watch. Emmy observe

s that Albert's watch is ticking more slowly than more quickly than at the same rate as her own watch.
Albert observes that Emmy's watch is ticking_______his own watch.
a. more slowly than
b. more quickly than
c. at the same rate as
Meanwhile, Emmy observes Albert's watch and compares it with her watch.
Emmy observes that Albert's watch is ticking_______ her own watch.
a. more slowly than
b. more quickly than
c. at the same rate as
Physics
1 answer:
alukav5142 [94]4 years ago
5 0

Answer:

1) b. more quickly than

Explanation:

It is stated in the question that Albert's watch is ticking more slowly than more quickly than at the same rate as her own watch.

Answer:

2) a. more slowly than

Explanation:

Albert's watch is ticking more slowly than more quickly than at the same rate as her own watch.

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A system initially has an internal energy E of 501 J. It undergoes a process during which it releases 111 J of heat energy to th
tresset_1 [31]

Answer:

The final energy of the system is 168 J

Explanation:

\triangle Q = \triangle U + W

Heat energy released to the surroundings, \triangle Q = -111 J

Work done, W = 222 J

-111 = \triangle U + 222\\ \triangle U = -111 - 222\\\triangle U = - 333 J

The initial internal energy, E_{1} = 501 J

The change in internal energy is given by the formula, \triangle U = E_{2} - E_{1}

E_{2}  = \triangle U + E_{1}\\E_{2} = -333 + 501\\E_{2} = 168 J

The final energy of the system is 168 J

3 0
3 years ago
A helium-filled balloon is launched when the temperature at ground level is 27.8°c and the barometer reads 752 mmhg. if the ball
ololo11 [35]
The helium may be treated as an ideal gas, so that
(p*V)/T =constant
where
p = pressure
V = volume
T = temperature.

Note that
7.5006 x 10⁻³ mm Hg = 1 Pa
1 L = 10⁻³ m³

Given:
At ground level,
p₁ = 752 mm Hg
     = (752 mm Hg)/(7.5006 x 10⁻³ mm Hg/Pa)
     = 1.0026 x 10⁵ Pa
V₁ = 9.47 x 10⁴ L = (9.47 x 10⁴ L)*(10⁻³ m³/L)
     = 94.7 m³
T₁ = 27.8 °C = 27.8 + 273 K
     = 300.8 K

At 36 km height,
P₂ = 73 mm Hg = 73/7.5006 x 10⁻³ Pa
     = 9.7326 x 10³ Pa
T₂ = 235 K

If the volume at  36 km height is V₂, then
V₂ = (T₂/p₂)*(p₁/T₁)*V₁
     = (235/9.7326 x 10³)*(1.0026 x 10⁵/300.8)*94.7
     = 762.15 m³

Answer: 762.2 m³  
3 0
3 years ago
Pigments are always made of natural materials
Kobotan [32]
It seems that you have missed the necessary options for us to answer this question so I had to look for it. Anyway, the answer to the given statement is FALSE. Pigments are NOT always made of natural materials. Pigments can either be man-made or the one that occurred naturally as what you see in our environment. Hope this helps.
5 0
3 years ago
A mass executes SHM at the end of a light spring. (a) What fraction of the total energy of the system is potential and what frac
PolarNik [594]

Answer:

Explained

Explanation:

A) The total energy of the system is defined by the energy at maximum amplitude, which we'll call A. At that point, the energy of the system is

E = 1/2×m×A^2;

since energy is conserved, this is also the total amount of energy that the system ever has.

So at x=1/2A,

the potential energy of the system is 1/8×m×A^2

which is one-fourth of the system's total energy. Therefore, the remaining three-fourths is kinetic.

B) (i) Doubling the maximum amplitude will quadruple the total energy:

E= \frac{1}{2}m(2A)^2

(ii) Doubling the maximum amplitude will double the maximum velocity

\frac{1}{2}m(2A)^2= \frac{1}{2}mV^2

(iii) Doubling the maximum amplitude will double the maximum acceleration: m×a = -k(2A)

(iv) Doubling the maximum amplitude leaves the period unchanged:

T= 2\pi\sqrt{\frac{m}{k} }

(neither m nor k has changed).

6 0
3 years ago
HELP !! Maura is deciding which hose to use to water her outdoor plants. Maura noticed that the water coming out of her garden h
MA_775_DIABLO [31]
THE GREEN HOSE:
Define the (x,y) coordinate at a height of 4 feet up from the ground to match where Majra is holding the green hose.
This means that the equation for the green hose is of the form
y = a(x - h)² + 4          (1)

Because water from the green hose lands on the ground 10 feet from where Majra is standing, therefore
y(10) = -4                    (2)

Because the curve passes through (0,0), therefore
ah² + 4 = 0
ah² = - 4                     (3)

To satisfy (2), obtain
a(10 - h)² + 4 = -4
a(10 - h)² = - 8            (4)

Divide (3) by (4).
h²/(10-h)² = 1/2
2h² = (10 - h)² = 100 - 20h + h²
h² + 20h - 100 = 0             

Solve with the quadratic formula.
x = 0.5[-20 +/- √(8400)] = 4.142, - 24.142
Reject the negative solution.
The vertex is at (4.142, 4).

From (3), obtain
a = -4/4.142² = -0.2332

The equation for the green hose is
y = 0.2332(x - 4.142)² + 4

THE RED HOSE
The red hose has a vertex at (3,7), according to the equation y = -(x-3)² + 7.

A graph of y(x) for both hoses is shown in the attached figure.

Answers:
a. The red hose will throw the water higher. 

b. The equation for the green hose is
     y = -0.2332(x - 4.124)² + 4,
     with the origin at a height of 4 feet above ground level.

c. The domain for the green hose that makes sense is 0 ≤ x ≤ 10 feet.
     The corresponding range is -4 ≤ y ≤ 4 feet.


3 0
3 years ago
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