Time required : 3 s
<h3>Further explanation
</h3>
Power is the work done/second.

To do 33 J of work with 11 W of power
P = 11 W
W = 33 J

The potential energy of a 30N ball on the ground will be zero. With respect to height, h. Potential energy will be calculated like this. P=mgh. So if its on the ground relatively speaking the h=0. Thus inputting into the above formula. P=0.
The work of Brian mind interface is to learn that’s my guess lol
Answer:
The mailbag will take 2.44 seconds to reach the ground.
Explanation:
The height of a helicopter above the ground is given by:

Height of helicopter at t = 2.10 seconds

The helicopter releases a small mailbag from the height of 29.17 m.
The initial velocity of mailbag = u = 0 m/s
Duration in which mailbag will reach the ground = T
Acceleration due to gravity = g = 
Using second equation of motion ;

We have , s = 29.17
u = 0 m/s
t = T

Solving for T, we gte :
T = 2.44 seconds
The mailbag will take 2.44 seconds to reach the ground.
Answer:
v = 17.66 m/s
Explanation:
As we know that the lower end of the pole is fixed in the ground and it start rotating about that end
so here we can say that the gravitational potential energy of the pole will convert into rotational kinetic energy of the pole about its one end
so we have

so we have

now we have


now the speed of the other tip of the pole is given as

