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Soloha48 [4]
3 years ago
8

A road with a positive cross slope is highest __________.

Physics
1 answer:
Alja [10]3 years ago
3 0

A road with a positive cross slope is highest in the center of the road.

The roads with Cross slopes are formed to provide the drainage system so that water will run off from the surface. Due to this no water stands on the roads, especially when there is heavy rain it is very useful. It is a very important safety factor.

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Which rational number could be graphed between 0 and 1?A number line going from negative 5 to positive 3 in increments of 1.Nega
vovikov84 [41]

In order to find which rational number is between 0 and 1, let's convert them into their decimal form:

\begin{gathered} \text{negative one-half:} \\ -\frac{1}{2}=-0.5 \\  \\ \text{one}-\text{fourth:} \\ \frac{1}{4}=0.25 \\  \\ \text{three}-\text{halves:} \\ 3\cdot\frac{1}{2}=\frac{3}{2}=1.5 \\  \\ 1.75 \end{gathered}

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7 0
1 year ago
If the length of a building is 2 1 2 times the width and each dimension is increased by 7 ft, then the perimeter is 266 ft. Find
N76 [4]

Answer:

The original dimensions of the building is 95 ft × 38 ft.

Explanation:

Let the original length be 'l' and original width be 'w'.

Given:

Original length (l) = 2\frac{1}{2}\times original\ width

Original width = 'w'.

So, l=2\frac{1}{2}w=\frac{5}{2}w

Now, as per question:

Length and width is increased by 7 ft.

So, new length (l') = l+7=\frac{5w}{2}+7

New width (w') = w+7

New perimeter (P) = 266 ft

Perimeter is given as:

P=2(l' +w')\\\\266=2(\frac{5w}{2}+w)\\\\\frac{266}{2}=\frac{5w+2w}{2}\\\\266=7w\\\\w=\frac{266}{7}=38\ ft

Therefore, original width = 38 ft.

Original length is, l=\frac{5\times 38}{2}=\frac{190}{2}=95\ ft

Hence, the original dimensions of the building is 95 ft × 38 ft.

7 0
4 years ago
when the elevator is moving upwards but its slowing to a stop at the top floor. what is the direction of the net force on the ri
Zielflug [23.3K]

Answer:Downward

Explanation:

As elevator is moving upward but is decelerating to stop at top

Suppose mg is the weight of man

N is the normal reaction

a is the acceleration

F_{net}=N-mg=m(-a)

here upward direction is positive while downward direction is negative

Therefore net force is in downward direction

8 0
4 years ago
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