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sergij07 [2.7K]
2 years ago
11

Line segment AB was dilated to create line segment A'B' using the dilation rule DQ,0.15. Point Q is the center of dilation. Line

segment A B is dilated to create smaller line segment A prime B prime. The length of Q A prime is 2.4. The length of A prime A is x. What is x, the distance between points A and A'? 2.4 units 4.8 units 13.6 units 14.4 units
Mathematics
1 answer:
Wewaii [24]2 years ago
7 0

Answer: 13.6 units

Step-by-step explanation:

Given the following :

Dilation rule : DQ, 0.15

The dilation factor is 0.15

Distance between Q and A' = 2.4

To calculate the distance 'x' between A and A'

The entire length of the side is calculated, that is, A to Q(center of dilation)

Length of A to Q = (Distance A' to Q) / dilation factor

Length of A to Q = 2.4 / 0.15 = 16

Distance (A to A') = x ;

Length AQ - length A'Q

16 - 2.4 = 13.6 units

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Answer:

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Step-by-step explanation:

The expressions provided are:

(i)\ x+((y\times (z')) +t)\\\\(ii)\ x\times((x+(y'))+z)

(i)

Simplify the first expression with as few symbols as possible:

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In a square, one pair of opposite sides was made 50% longer and the other pair of opposite sides was made 50% shorter.
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