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sergij07 [2.7K]
3 years ago
11

Line segment AB was dilated to create line segment A'B' using the dilation rule DQ,0.15. Point Q is the center of dilation. Line

segment A B is dilated to create smaller line segment A prime B prime. The length of Q A prime is 2.4. The length of A prime A is x. What is x, the distance between points A and A'? 2.4 units 4.8 units 13.6 units 14.4 units
Mathematics
1 answer:
Wewaii [24]3 years ago
7 0

Answer: 13.6 units

Step-by-step explanation:

Given the following :

Dilation rule : DQ, 0.15

The dilation factor is 0.15

Distance between Q and A' = 2.4

To calculate the distance 'x' between A and A'

The entire length of the side is calculated, that is, A to Q(center of dilation)

Length of A to Q = (Distance A' to Q) / dilation factor

Length of A to Q = 2.4 / 0.15 = 16

Distance (A to A') = x ;

Length AQ - length A'Q

16 - 2.4 = 13.6 units

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Step-by-step explanation:

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3 years ago
A 3 cm x 3 cm rectangle sits inside a circle with radius of 4 cm.
Vitek1552 [10]

Given:

Rectangle inside a circle.

To find:

The area of the shaded region.

Solution:

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Width of a rectangle = 3 cm

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5 0
4 years ago
Read 2 more answers
Help me on calculating the area of the shaded part
Ymorist [56]

Answer:

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Step-by-step explanation:

Find the area of the square - area of 4 sectors

We'll use the formula to find one sector area

a =  \frac{1}{2}  \times  {r}^{2}  \times x

where r is the radius of one sector and x is the angle in radians

Since each angle is in a square, the angle of the sectors is 90 degrees.

Convert degrees to radians

90 =  \frac{1}{2} \pi \: rad

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One sector area:

\frac{1}{2}  \times {35}^{2}  \times  \frac{1}{2} \pi = 306.25\pi

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4 \times 306.25\pi = 1225\pi

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70 \times 70  = 4900

Hence, Area of square - 4 Sectors:

4900 - 1225\pi = 1051.55 {mm}^{2} (2dp)

6 0
3 years ago
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