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AnnZ [28]
4 years ago
8

HELP ASAP PLS............

Mathematics
1 answer:
lara31 [8.8K]4 years ago
6 0
What do you need help with??

:)
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Can someone please help me with number 6? If so, you get 11 points!
andrew-mc [135]

we just have to find x
so,
20-x=6
     do it like this  
    -x = 6-20
   -x = -14 
    x = 14 is the write answer
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3 years ago
The principal of Fremont High School is putting together a table that lists student attendance at four types of events held at t
Ghella [55]

Answer:

Step-by-step explanation:

The answer is 2050

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3 years ago
What is the solution of the equation (x – 5)2 3(x – 5) 9 = 0? use u substitution and the quadratic formula to solve.
Ahat [919]

The value of x in the equation (x-5)^{2} +3(x-5)+9=0is x=(7+3\sqrt{3}i)/2,

(7-3\sqrt{3}i)/2.

Given equation (x-5)^{2} +3(x-5)+9=0 .

We have to find the solution of the equation.

Equation  is solved to find the value of variables. The number of values of the variable depends on the highest power of variables.

let (x-5)=u-------------------1

equation becomes u^{2} +3u+9=0

solution of a quadratic formula

x=-b±\sqrt{b^{2} -4ac}/2a

on comparing with general form a=1,b=3, c=9

u=-3±\sqrt{3^{2} -4*1*9} /2

=-3±\sqrt{9-36}/2

=-3±3\sqrt{-27}/2

=-3±3\sqrt{3} i/2

u_{1} =-3+3\sqrt{3}/2 , u_{2}=-3-3\sqrt{3}/2

put the values of u_{1} in equation 1

x-5=u_{1}

x-5=-3+3\sqrt{3} /2

x=-3+3\sqrt{3}i/2+5

x=7+3\sqrt{3} i/2

put the values of u_{2} in  equation2

x-5=u_{2}

x-5=-3-3\sqrt{3} /2

x=7-3\sqrt{3}/2

Hence the values of x are 7+3\sqrt{3}i/2, 7-3\sqrt{3}i/2.

Learn more about equation at brainly.com/question/2972832

#SPJ4

5 0
2 years ago
Can someone help me out on this problem and show work please
horsena [70]

Answer:

4230.14

Step-by-step explanation:

2040/1700=1.2

2448x1.2=2937.6

2937.6x1.2=3525.12

3525.12x1.2=4230.144

round to the nearest hundredth

4230.14

brainliest please

7 0
2 years ago
What is the square root of 1200?
alukav5142 [94]
<span>34.6410161514 is the answer

Hope this helped :)</span>
4 0
3 years ago
Read 2 more answers
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