All categories

3 years ago

39 is what percent of 156?

Mathematics

2 answers:

marshall27 [118]3 years ago

6 0

The answer Is 25% of 156

sashaice [31]3 years ago

4 0

Since 39/156 can be simplified to 1/4, 1/4 of 100% is 25%.

You might be interested in

What's the answer 2(×+4)=18

Nadusha1986 [10]

2(x+4)=18

2•x + 2•4 = 18

2x + 8 = 18

2x + 8 = 18
- 8 -8
_________
2x = 10

2x = 10
__ __
÷2 ÷2

x = 5

5 0

3 years ago

Read 2 more answers

Flora made 4 withdrawals of $80 each from her bank account. What was the overall change

Len [333]

Answer:

$320 if your saying how much in all its basically 8 times 4 add a zero to the end

Step-by-step explanation:

4 0

3 years ago

Suppose that \nabla f(x,y,z) = 2xyze^{x^2}\mathbf{i} + ze^{x^2}\mathbf{j} + ye^{x^2}\mathbf{k}. if f(0,0,0) = 2, find f(1,1,1).

lesya [120]

The simplest path from (0, 0, 0) to (1, 1, 1) is a straight line, denoted $C$ , which we can parameterize by the vector-valued function,

$\mathbf r(t)=(1-t)(\mathbf i+\mathbf j+\mathbf k)$

for $0\le t\le1$ , which has differential

$\mathrm d\mathbf r=-(\mathbf i+\mathbf j+\mathbf k)\,\mathrm dt$

Then with $x(t)=y(t)=z(t)=1-t$ , we have

$\displaystyle\int_{\mathcal C}\nabla f(x,y,z)\cdot\mathrm d\mathbf r=\int_{t=0}^{t=1}\nabla f(x(t),y(t),z(t))\cdot\mathrm d\mathbf r$

$=\displaystyle\int_{t=0}^{t=1}\left(2(1-t)^3e^{(1-t)^2}\,\mathbf i+(1-t)e^{(1-t)^2}\,\mathbf j+(1-t)e^{(1-t)^2}\,\mathbf k\right)\cdot-(\mathbf i+\mathbf j+\mathbf k)\,\mathrm dt$

$\displaystyle=-2\int_{t=0}^{t=1}e^{(1-t)^2}(1-t)(t^2-2t+2)\,\mathrm dt$

Complete the square in the quadratic term of the integrand: $t^2-2t+2=(t-1)^2+1=(1-t)^2+1$ , then in the integral we substitute $u=1-t$ :

$\displaystyle=-2\int_{t=0}^{t=1}e^{(1-t)^2}(1-t)((1-t)^2+1)\,\mathrm dt$

$\displaystyle=-2\int_{u=0}^{u=1}e^{u^2}u(u^2+1)\,\mathrm du$

Make another substitution of $v=u^2$ :

$\displaystyle=-\int_{v=0}^{v=1}e^v(v+1)\,\mathrm dv$

Integrate by parts, taking

$r=v+1\implies\mathrm dr=\mathrm dv$

$\mathrm ds=e^v\,\mathrm dv\implies s=e^v$

$\displaystyle=-e^v(v+1)\bigg|_{v=0}^{v=1}+\int_{v=0}^{v=1}e^v\,\mathrm dv$

$\displaystyle=-(2e-1)+(e-1)=-e$

So, we have by the fundamental theorem of calculus that

$\displaystyle\int_C\nabla f(x,y,z)\cdot\mathrm d\mathbf r=f(1,1,1)-f(0,0,0)$

$\implies-e=f(1,1,1)-2$

$\implies f(1,1,1)=2-e$

3 0

3 years ago

Lucas and Tayvan can paint a house in 1 hour working together. If Tayvan works alone, he can paint the house in 1.5 hours. How l

nikitadnepr [17]

Answer:

1 hour

Step-by-step explanation:

no explanation its common sense lol

7 0

3 years ago

Lily just paid off a $400 loan. She had to pay $60 in interest at a simple annual interest rate of 5%. How many years did Lily h

SCORPION-xisa [38]

Answer:

I=prt,,60=400*0.05t,,t=3 ..................

this is what i got i hope it is use full to you <3

Step-by-step explanation:

4 0

3 years ago