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Korolek [52]
3 years ago
13

PLZ HELP ASAP WILL GIVE BRAINLIEST :)!!!

Mathematics
1 answer:
Kobotan [32]3 years ago
3 0
9 students earned an 85 or higher.

2 earned 85
1 earned 86
3 earned 91
1 earned 94
2 earned 95.

2+1+3+1+2=9
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Select the correct answer. A model rocket was launched from the top of a building. The rocket's approximate height can be modele
garri49 [273]

Answer:

13 seconds.

Step-by-step explanation:

Given

h = -4.9(t - 13)(t + 2).

Required

Determine a reasonable solution for t

To do this, we equate h to 0.

h = -4.9(t - 13)(t + 2). becomes

0 = -4.9(t - 13)(t + 2).

Divide through by -4.9

0 = (t - 13)(t + 2).

Reorder the expression

(t - 13)(t + 2) = 0.

Split

t-13 = 0 or t + 2 = 0

This gives:

t = 13 or t = -2

But time can't be negative, So:

t = 13

6 0
3 years ago
Numbers whose decimals do not end and do not repeat are
eduard

Answer:

It's an irrational number

Step-by-step explanation:

Examples:

√2 = 1.4142135623730950488016887242096980785696718...

π = 3.14159265358979323846264338327950288419716939...

e =  2.718281828459045235360287...

∛10 = 2.1544346900318837217592935665193504952593449421921...

and more

If the number has a finite or repeating decimal, then it is a rational number.

Examples:

2.75

-1.3333...

0.4545454545...

6 0
3 years ago
Read 2 more answers
Find the horizontal and vertical asymptotes of​ f(x). ​f(x) equals = StartFraction 6 x Over x plus 2 EndFraction 6x x+2 Find the
miss Akunina [59]

Answer:

The horizontal asymptote can be described by the line y = 6

The vertical asymptote can be described by the line x = -2

Step-by-step explanation:

* <em>Lets the meaning of vertical and horizontal asymptotes</em>

- <u><em>Vertical asymptotes</em></u> are vertical lines which correspond to the zeroes

  of the denominator of a rational function

- <u><em>A horizontal asymptote</em></u> is a y-value on a graph which a function

 approaches but does not actually reach

- If the degree of the numerator is less than the degree of the

 denominator, then there is a horizontal asymptote at y = 0

- If the degree of the numerator is greater than the degree of the

 denominator, then there is no horizontal asymptote

- If the degree of the numerator is equal the degree of the denominator,

 then there is a horizontal asymptote at y = leading coefficient of the

 numerator ÷ leading coefficient of the denominator

* <em>Lets solve the problem</em>

∵ f(x)=\frac{6x}{x+2}

∵ The numerator is 6x

∵ The denominator is x + 2

∴ The numerator and the denominator have same degree

∵ The leading coefficient of the numerator is 6

∵ The leading coefficient of the denominator is 1

∴ There is a horizontal asymptote at y = 6/1

∴ <em>The horizontal asymptote can be described by the line y = 6</em>

- Put the denominator equal zero to find its zeroes

∵ The denominator is x + 2

∴ x + 2 = 0

- Subtract 2 from both sides

∴ x = -2

∴ <em>The vertical asymptote can be described by the line x = -2</em>

6 0
3 years ago
Read 2 more answers
Literally the last question pls get it right
Anna11 [10]
-1 or option c is correct. Use the given functions to set up and simplify f(−2).
5 0
3 years ago
Read 2 more answers
How does solving the equation arithmetically compare to solving an equation algebraically
IRISSAK [1]
In an arithmetic equation, there is no variable in the 'meat' of the equation(example: 5-5=0). In an algebraic equation, there is a variable in the meat of the equation(example: 5-x=0).
Hope this helps and please give brainliest!
4 0
3 years ago
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