The given question is wrong.
Question:
What is the standard form of ?
Answer:
The standard form of the given equation is .
Solution:
The given equation is .
The equation is not in the standard form.
To write the equation in the standard form.
The standard form of the quadratic equation is .
⇒
⇒
Hence the standard form of the given equation is .
Answer:
2 and 4 are correct
Step-by-step explanation:
1 is incorrect because 4/5 being bigger than 7/10
3 is incorrect because 2/3 is more than 5/9
Answer: 21/4 or 5 1/4
Step-by-step explanation: sorry for the 21/4 if this is wroNG IM SOOO SORRy if it is..
The correct answer is C: y > 2/3x + 3
(1,4) ⇒ within the shaded region
4 > 2/3(0) + 3
4 > 0 + 3
4 > 3
True
(0,0) ⇒ within the unshaded region
0 > 2/3(0) + 3
0 > 0 + 3
0 > 3
False
<h3>
Answer: ds/dt = 11</h3>
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Work Shown:
Before we can use derivatives, we need to find the value of s when (x,y) = (15,20)
s^2 = x^2+y^2
s^2 = 15^2+20^2
s^2 = 225+400
s^2 = 625
s = sqrt(625)
s = 25
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Now we can apply the derivative to both sides to get the following. Don't forget to use the chain rule.
s^2 = x^2 + y^2
d/dt[s^2] = d/dt[x^2 + y^2]
d/dt[s^2] = d/dt[x^2] + d/dt[y^2]
2s*ds/dt = 2x*dx/dt + 2y*dy/dt
2(25)*ds/dt = 2(15)*5 + 2(20)*(10)
50*ds/dt = 150 + 400
50*ds/dt = 550
ds/dt = 550/50
ds/dt = 11
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Side note: The information t = 40 is never used. It's just extra info.