Parabola
remember that
parabola equation is
4p(y-k) =(x-h)^2 for a verticl parabola
p=distance from vertex to focus and from vertex to directix
solve for p, k, h
y=0.6x^2
4p(y-0)=(x-0)^2
divide both sides by 4p
(y-0)=1/4p times (x-0)^2
y=0.6x^2
1/(4p)=0.6
find p
multiply 4p
1=2.4p
divide 2.4
1/2.4=p
h=0,k=0
vertex=0,0
opens up so go up to find focus
(0,0)
0+1/2.4=1/2.4
focus is at (0,1/2.4)
The first coordinate is given the letter x and the second coordinate is given the letter y. Thus, we have that we need to substitute in the formula of the transformation 2 for x and -1 for y. Hence, we have that the image of A is given by: T(A)= (2-5, -1+3)= (-3, 2).
No. For example,
gives you a 2, which isn't a recurring decimal! You can try this for all sorts of multiples of 9 and you will see that they do not give you recurring decimals. However, there are some, e.g.
which gives you 1.1111111....
Hope this helps!
Answer:
20-2(n-1)
Step-by-step explanation:
The general term (or the nth term) of this sequence is [20-2(n-1)].
Verification:
1st term = 20-2(1-1) = 20-2(0) = 20-0 = 20
2nd term = 20-2(2-1) = 20-2(1) = 20-2 = 18
3rd term = 20-2(3-1) = 20-2(2) = 20-4 = 16
4th term = 20-2(4-1) = 20-2(3) = 20-6 = 14
Answer:
xy - 3
Step-by-step explanation:
Product of x and y = xy
Required number = xy - 3
