Force = (mass) x (acceleration)
Mass = (force) / (acceleration)
There was 150N of force in one direction and 100N of 'force' in
the other direction. The net force on the object was (150 - 100) = 50N .
Acceleration = (change in speed) / (time for the change)
= (10 m/s) / (5s) = 2 m/s²
Mass = (net force) / (acceleration) = (50 N) / (2 m/s²) = 25 kilograms
The transmission of light waves is usually done through cornea of the eyes, then move through another opening which is regarded as pupil before it will get to the retina.
- Light waves can be regarded as moving energy which contains microscopic particles known as photons.
- The vision of the eye can be completed through the light wave passing through the components of the eyes and this process goes thus;
- Light will move through the (cornea) which is situated at the front area of the eyes into lens.
- Then both the cornea and the lens give room for the focusing of the light rays to the retina which is situated at the back of the eye .
- Then through the help of the cells in the retina, the light will be absorbed and then be converted to electrochemical impulses and then transfer it to the brain as well as optic nerve.
Therefore, light wave are form of tiny microscopic particles.
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Answer:
Option D is correct: 170 µW/m²
Explanation:
Given that,
Frequency f = 800kHz
Distance d = 2.7km = 2700m
Electric field Eo = 0.36V/m
Intensity of radio signal
The intensity of radial signal is given as
I = c•εo•Eo²/2
Where c is speed of light
c = 3×10^8m/s
εo = 8.85 × 10^-12 C²/Nm²
I = 3×10^8 × 8.85×10^-12 × 0.36²/2
I = 1.72 × 10^-4W/m²
I = 172 × 10^-6 W/m²
I = 172 µW/m²
Then, the intensity of the radio wave at that point is approximately 170 µW/m²
