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tester [92]
3 years ago
12

On the coordinate plane below, draw the vector that goes from (0,0) to (2,3)

Physics
1 answer:
Vladimir [108]3 years ago
7 0

Simply draw the vector with the given coordinates.

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Condyloid joints are, logically enough, created by joints at condyle bone markings.
Finger [1]

Answer: False

Explanation:

It's received in elliptical cavities.

7 0
2 years ago
Measuring a liquid's volume indicated the capacity ______ of the holds it. The most common units for expressing liquid volumes a
Amiraneli [1.4K]

Answer:

Measuring, comparing and estimating liquid volumes are taught using metric units like liters and milliliters and customary units like quart, pints, gallons and more. Capacity is actually the amount of liquid in the container, which is also the volume of a liquid.

Explanation:

5 0
2 years ago
5. Find the mass of a car that is traveling at a velocity of 35 m/s West.
sattari [20]

Answer:

m = 9795.9 kg

Explanation:

v = 35 m/s

KE = 6,000,000 J

Plug those values into the following equation:

KE = \frac{1}{2} mv^{2}

6,000,000 J = (1/2)(35^2)m

---> m = 9795.9 kg

3 0
3 years ago
The height (in meters) of a projectile shot vertically upward from a point 2 m above ground level with an initial velocity of 22
alexgriva [62]
1) The law of motion of the projectile is
h(t) = 2+22.5 t-4.9 t^2
To find the velocity, we should compute the derivative of h(t):
v(t)=h'(t)=22.5-2\cdot 4.9t=22.5-9.8t
So now we can calculate the speed at t=2 s and t=4 s:
v(2.0s)=22.5-9.8\cdot2.0 =2.9 m/s
v(4.0s)=22.5-9.8\cdot 4.0s=-16.7 m/s
The negative sign in the second speed means the projectile has already reached its maximum height and it is now going downward.

2) The projectile reaches its maximum height when the speed is equal to zero:
v(t)=0
So we have
22.5-9.8 t=0
And solving this we find
t=2.30 s

3) To find the maximum height, we take h(t) and we just replace t with the time at which the projectile reaches the maximum height, i.e. t=2.30 s:
h(2.30 s)=2+22.5\cdot 2.30 -4.9 \cdot (2.30s)^2 = 27.83 m

4) The time at which the projectile hits the ground is the time at which the height is zero: h(t)=0. So, this translates into
2+22.5t -4.9 t^2 = 0
This is a second-order equation, and if we solve it we get two solutions: the first solution is negative, so we can ignore it since it's physically meaningless; the second solution is
t=4.68 s
And this is the time at which the projectile hits the ground.

5) The velocity of the projectile when it hits the ground is the velocity at time t=4.68 s:
v(4.68 s)=22.5-9.8\cdot 4.68 =-23.36  m/s
with negative sign, because it is directed downward.
8 0
3 years ago
PLEASE HELP:
german

Answer:

3.39 mins.

10m/s multiplied by 6 equals to 60 seconds or 1 minute

7 0
2 years ago
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