The dosage in milligrams D of a heartworm preventive for a dog who weighs x pounds is given by D(x) =136/25x.
1 answer:
Answer:
130.56 mg
Step-by-step explanation:
The equation might be written incorrectly. Given that for a heavier dog, a higher dosage is required, the equation that describes the dosage in milligrams of a heartworm preventive for a dog who weighs x pounds is:
If a dog weighs 24 pounds, than the dosage required for this dog is:
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Answer:
The coordinates of the endpoints of the side congruent to side EF is:
E'(-8,-4) and F'(-5,-7).
Step-by-step explanation:
<em>" when point M (h, k) is rotated about the origin O through 90° in anticlockwise direction or we can say counter clockwise. The new position of point </em><em>M (h, k) will become M' (-k, h) "</em>
We are given a trapezoid such that the vertices of trapezoid are:
E(-4,8) , F(-7,5) , G(-4,3) , H(-2,5)
Then the new coordinates after the given transformation is:
E(-4,8) → E'(-8,-4)
F(-7,5) → F'(-5,-7)
G(-4,3) → G'(-3,-4)
H(-2,5) → H'(-5,-2)
Hence the coordinates of the endpoints of the side congruent to side EF is:
E'(-8,-4) and F'(-5,-7).
