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2 years ago

If two sides of a rectangle are 5 units and 9 units, what is the perimeter?

1 answer:

3 0

The perimeter is 28 bc 5+5 is 10 and 9+9 is 18 so if you add 10 and 18 you get 28. Hope it helps:)
(please mark brainliest )

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Which sequence of transformations will verify that quadrilateral WTUV and quadrilateral W'T'U'V' are congruent? A) WTUV is moved

andrew-mc [135]

Answer:

A) WTUV is moved onto W'T'U'V' after translating −15 units vertically, and then rotating 180° counterclockwise around the origin.

Step-by-step explanation:

WTUV is moved onto W'T'U'V' after translating −15 units vertically, and then rotating 180° counterclockwise around the origin.

6 0

2 years ago

A salesperson earns $200 a week plus a 4% commission on her sales. Which equation models the relationship between her sales in a

trasher [3.6K]

In this problem, we have the following variables:

e: The weekly earnings of a salesperson

s: sales in a given week

A salesperson earns $200 a week plus a 4% commission on her sales, that is, she earns:

<em>$200 plus 0.04 of her sales in a given week</em>

In a mathematical model, this is given by:

e = 200 + 0.04s

6 0

2 years ago

Read 2 more answers

WORTH ALOT OF POINTS!!

strojnjashka [21]

Answer:

B is the answer!!!

Step-by-step explanation:

the tape diagram shows this

5 0

3 years ago

Read 2 more answers

Let θ

konstantin123 [22]

Answer:

θ is decreasing at the rate of $\frac{21}{16}$ units/sec

or $\frac{d}{dt}$ (θ) = $\frac{-21}{16}$

Step-by-step explanation:

Given :

Length of side opposite to angle θ is y

Length of side adjacent to angle θ is x

θ is part of a right angle triangle

At this instant,

x = 8 , $\frac{dx}{dt}$ = 7

( $\frac{dx}{dt}$ denotes the rate of change of x with respect to time)

y = 8 , $\frac{dy}{dt}$ = -14

( The negative sign denotes the decreasing rate of change )

Here because it is a right angle triangle,

tanθ = $\frac{y}{x}$ -------------------------------------------------------------------1

At this instant,

tanθ = $\frac{8}{8}$ = 1

Therefore θ = π/4

We differentiate equation (1) with respect to time in order to obtain the rate of change of θ or $\frac{d}{dt}$ (θ)

$\frac{d}{dt}$ (tanθ) = $\frac{d}{dt}$ (y/x)

( Applying chain rule of differentiation for R.H.S as y*1/x)

$sec^{2}$ θ $\frac{d}{dt}$ (θ) = $\frac{1}{x}$ $\frac{dy}{dt}$ - $\frac{y}{x*x}$ $\frac{dx}{dt}$ -----------------------2

Substituting the values of x , y , $\frac{dx}{dt}$ , $\frac{dy}{dt}$ , θ at that instant in equation (2)

2 $\frac{d}{dt}$ (θ) = $\frac{1}{8}$ *(-14)- $\frac{8}{8*8}$ *7

$\frac{d}{dt}$ (θ) = $\frac{-21}{16}$

Therefore θ is decreasing at the rate of $\frac{21}{16}$ units/sec

or $\frac{d}{dt}$ (θ) = $\frac{-21}{16}$

3 0

3 years ago

A regular hexagon with side length 4 has the same area as a square. What is the length of the square?

svetlana [45]

Answer: The length of the square is $6.44$

Step-by-step explanation:

By definition, the area of a Regular polygon can be calculated with the following formula:

$A=\frac{s^2n}{4tan(\frac{180}{n})}$

Where "s" the length of any side of the polygon and "n" is the number of sides .

According to the information given in the exercise, you know that:

$s=4$

Since an hexagon has six sides, you know that:

$n=6$

Therefore, its area is:

$A_h=\frac{(4^2)(6)}{4tan(\frac{180}{6})}\\\\A_h=24\sqrt{3}$

The formula to find the area of a square is:

$A=s^2$

Where "s" is the length of any side of the square.

Since that regular hexagon has the same area as this square, you can substituting the area calculated above into the formula for calculate the area of a square, and then solve for "s".

Then you get:

$24\sqrt{3}=s^2\\\\\sqrt{24\sqrt{3}}=s\\\\s=6.44$

7 0

3 years ago