The position of the centre of gravity of an object affects its stability. The lower the centre of gravity (G) is, the more stable the object. The higher it is the more likely the object is to topple over if it is pushed. Racing cars have really low centres of gravity so that they can corner rapidly without turning over.
Increasing the area of the base will also increase the stability of an object, the bigger the area the more stable the object. Rugby players will stand with their feet well apart if they are standing and expect to be tackled.
Answer:
1058.78 ft/sec
Explanation:
Horizontal Component of Velocity; This is the velocity of a body that act on the horizontal axis. I.e Velocity along x-axis
The horizontal velocity of a body can be calculated as shown below.\
Vh = Vcos∅.......................... Equation 1
Where Vh = horizontal component of the velocity, V = The velocity acting between the horizontal and the vertical axis, ∅ = Angle the velocity make with the horizontal.
Given: V = 1178 ft/sec, ∅ = 26°
Substitute into equation 1
Vh = 1178cos26
Vh = 1178(0.8988)
Vh = 1058.78 ft/sec
Hence the horizontal component of the velocity = 1058.78 ft/sec
Answer:
Momentum is conserved in all three physical directions at the same time.
Explanation:
There is a peculiarity, however, in that momentum is a vector, involving both the direction and the magnitude of motion, so that the momenta of objects going in opposite directions can cancel to yield an overall sum of zero.
<h3><u>Answer;</u></h3>
= 2868 Newtons
<h3><u>Explanation;</u></h3>
Centripetal force is a force that acts on an object or a body in circular path and is directed towards the center of the circular path.
Centripetal force is given by the formula;
mv²/r ; where m is the mass of the body, r is the radius of the circular path and v is the velocity of a body;
mass = 65 kg, velocity = 15 m/s and r = 5.1 m
Therefore;
Centripetal force = (65 × 15²)/ 5.10
= 2867.65 Newtons
= 2868 N
Answer:
F1 is equal to F2
Explanation:
Here
F1 is the gravitational force exerted by the earth on the satellite.
F2 is the gravitational force exerted by the satellite on the earth.
Now these two forces are equal but opposite in nature. This is given by the Third law of motion by Newton. According to this law, when there is force exerted between two objects, one force is balanced the other force which is equal in magnitude and opposite in nature.
Thus the gravitational force of the earth exerted on the satellite is equal to the force exerted by the satellite on the earth.
Hence F1 = F2.
