Question

Two forces, of magnitudes 140 and 237 newtons respectively, act at a point in the plane. The angle between the forces is 73°. Find the magnitude of the resultant force.

Answer 1

309 N is the magnitude of the resultant force formed by two forces of magnitudes 140 and 237 newton respectively, act at a point in the plane.

The resultant vector of two vectors:

P and Q is given by

R= $\sqrt{ P^2 + Q^2+ 2PQcos\theta}$

​where, P and Q are magnitudes of two vectors and θ is the angle between two vectors.

Here θ=73⁰  P=140N  Q=237N  R=?                 ( cos 73⁰  = 0.3)+19908

Therefore,

R= $\sqrt{140^2 + 237^2 + 2 *140*237*cos 73^o }$

R = √19600 +56169+19908

R = √95677

R = 309 N

​The parallelogram law of vector addition is a method that is used to find the sum of two vectors in vector theory.

We study two laws for the addition of vectors -

• the triangle law of vector addition
• the parallelogram law of vector addition.

The parallelogram law of vector addition is used to add two vectors when the vectors that are to be added form the two adjacent sides of a parallelogram by joining the tails of the two vectors. Then, the sum of the two vectors is given by the diagonal of the parallelogram.

Learn more about parallelogram law of vector addition here : brainly.com/question/26056717

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