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mamaluj [8]
3 years ago
6

Please Help Conservation of energy

Physics
1 answer:
Sonja [21]3 years ago
8 0

Answer:

a principle stating that energy cannot be created or destroyed, but can be altered from one form to another.

Explanation:

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What will be the value of both charges if they are 5 cm apart and suffer a
Mrac [35]

Answer:

\boxed{q = 1.2 \times  {10}^{ - 6} C}

Explanation:

f_e =   \frac{{q}^{2}k }{ {r}^{2} }  \\ q =  \sqrt{ \frac{f_e( {r}^{2} )}{k} }  =  \sqrt{ \frac{5.2(5 \times  {10}^{ - 2} )^{2} }{9 \times  {10}^{9} } }  \\ q =\sqrt{ \frac{5.2(5 \times  {10}^{ - 2} )^{2} }{9 \times  {10}^{9} } }  =  \sqrt{ \frac{0.013}{9 \times  {10}^{9} } }  \\ q = 1.2 \times  {10}^{ - 6}

3 0
2 years ago
A 4.40-kilogram hoop starts from rest at a height 1.70 m above the base of an inclined plane and rolls down under the influence
Anestetic [448]

Answer:

The linear velocity is  v=4.08m/s

Explanation:

According to the law of conservation of energy

   The potential energy possessed by the  hoop at the top of the inclined plane is converted to the kinetic energy at the foot of the inclined plane

        The kinetic energy can be mathematically represented as

                    KE = \frac{mv^2}{2} + \frac{Iw}{2}

Where I is the moment of inertia possessed by the hoop  which is mathematically represented as

                 I = mr^2

Here R is the radius of the hoop

         w is the angular velocity which the hoop has at the bottom of the lower part of the inclined plane which is mathematically represented as

                          w = \frac{v}{r}

Where v linear speed of the hoop's center of mass just as the hoop leaves the incline and rolls onto a horizontal surface

      Now expressing the above statement mathematically

            potential \ energy = \frac{mv^2}{y} + \frac{Iw^2}{2}

               mgh = \frac{mv^2}{y} + \frac{Iw^2}{2}

=>            mgh =\frac{mv^2}{2} + \frac{(mr^2)(\frac{v}{r})^2 }{2}  

=>          mgh = \frac{mv^2}{2} + \frac{mv^2}{2}

=>           mgh = mv^2

=>              v = \sqrt{gh}

Substituting values

                v = \sqrt{9.81 * 1.7}

                  v=4.08m/s

4 0
3 years ago
Read 2 more answers
What is the difference between balanced and unbalanced forces
max2010maxim [7]

Answer:

Explanation:

When the two or more forces acting on a body such tat the net force on the body or the acceleration of the body is zero, then such forces are balanced forces.

For example, in the game of tug of war, both the teams pulls the rope with same force but in opposite directions so that the net acceleration is zero it means a balanced force is acting on the rope.

When tow or more forces acting on a body and there is some net force or acceleration of the body, then the forces are said to be unbalanced.

For example, if we push a box along the plane, the net force is non zero and the forces are unbalanced.

4 0
3 years ago
if a sine wave representing ac voltage has an effective value of 70 vac what would be the waves peak value​
Morgarella [4.7K]

Answer:

99 V

Explanation:

The effective voltage of an AC current (also called rms voltage) is given by

V_{rms} = \frac{V_0}{\sqrt{2}}

where

Vrms is the rms voltage

V0 is the peak voltage

In this problem, we know the effective voltage:

V_{rms} = 70 V

Therefore, we can re-arrange the equation to find the peak voltage:

V_0 = V_{rms} \sqrt{2} =(70 V)(\sqrt{2})=99 V

3 0
3 years ago
Derive velocity-time relation from velocity-time graph ​
Brrunno [24]

Explanation:

hope this helps you

.....,.......

7 0
3 years ago
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