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3 years ago

Please Help Conservation of energy

Physics

1 answer:

Sonja [21]3 years ago

8 0

Answer:

a principle stating that energy cannot be created or destroyed, but can be altered from one form to another.

Explanation:

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What happens to the change in the value of the speed as you increased the amount of force applied on your

nataly862011 [7]

The change of speed is proportional to the Force. If you double the Force, you double the change of speed.

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2 years ago

What would be the Elastic Potential Energy (EPE) stored in a spring with a constant k = 200 N/m that is pulled to stretch 0.45m?

harkovskaia [24]

Answer:

During the summer, oxygen is supplied by surface winds. M/NPT 16 to 26 0.14 to 0.45 m 1/ 77.80 $ 28 Phone: 418 81-1 Fax: 418 81-2882 SZ5-2025 SZ22-200 SZ2-250 SZ24-00 12.5 x 60 12.5 x 60 12.5 x 60 8 x 10 10 x 15 10 x 20 15 x HI-950 can take measures between 0.1 C to 999.9 C/ F. K, J & T-type: The HI-9551

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2 years ago

To model this process, assume two charged spherical conductors are connected by a long conducting wire and a 1.20-mC charge is p

il63 [147K]

Answer:

Part a: The electric potential of each sphere is 1.35x10⁸V

Part b: The electric field at the surface of sphere 1 and 2 is 2.25x10⁹ N/C and 6.75x10⁹ N/C respectively

Explanation:

As the complete question is not given, the similar question is attached herewith. The values are used as indicated in the given question

Let r_1 = 6 cm=0.06 m

r2 = 2 cm = 0.02 m

Q = 1.2 mC

Let q1 and q2 are the charges on each sphere.

q1 + q2 = 1.2 mC -------(1)

In the equilibrium, V1 = V2

k*q1/r1 = k*q2/r2

q1/0.06 = q2/0.02

q1/q2 = 0.06/0.02

q1/q2 = 3 ---------(2)

On solving equation 1 and 2

we get

q1 = 0.9 mC

q2 = 0.3 mC

V1 = k*q1/r1 = (9*10^9*0.9*10^-3)/0.06 = 1.35*10^8 Volts

V2 = k*q2/r2 = 9*10^9*0.3*10^-3/0.02 = 1.35*10^8 Volts

So the electric potential of each sphere is 1.35x10⁸V

Part b

Now the electric potential is given as

E1 = k*q1/r1^2 = 9*10^9*0.9*10^-3/0.06^2 = 2.25*10^9 N/C

E2 = k*q2/r2 = 9*10^9*0.3*10^-3/0.02^2 = 6.75*10^9 N/C

So the electric field at the surface of sphere 1 and 2 is 2.25x10⁹ N/C and 6.75x10⁹ N/C respectively

7 0

3 years ago

Sketch the electric field around these two objects if they have the same sign of charge. Make a separate drawing showing equipot

diamong [38]

Answer:

* far from one of the charges, the field of the other charge is small and can be neglected

* on the outside of the loads the fields are added territorially

* between the charges the two fields tend to vanish

Explanation:

The electric field around two objects with charge of the same sign, for simplicity suppose that the objects have positive point spherical charges,

E = k q / r2

bold letters indicate vectors, therefore the total electric field is

E_total = E1 + E2

the module of this field is

E_total = E1- E2

therefore we can outline this field

* far from one of the charges, the field of the other charge is small and can be neglected

* on the outside of the loads the fields are added territorially

* between the charges the two fields tend to vanish

An outline of these shows in Attachment A

The equipotential surfaces are defined as being perpendicular to the electric field lines since the electric field and the power difference are related

E = $\frac{dV}{dx} i^ + \frac{dV}{dy} j^ + \frac{dV}{dz} k^ = \Delta V$