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mamaluj [8]
3 years ago
6

Please Help Conservation of energy

Physics
1 answer:
Sonja [21]3 years ago
8 0

Answer:

a principle stating that energy cannot be created or destroyed, but can be altered from one form to another.

Explanation:

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Explain how the gravitational potential energy of an object can be changed.
inna [77]

Answer:

Change in Potential energy, pe = Final potential energy - Initial potential energy

Explanation:

∆p.e = Final p.e - Initial p.e

From the equation ∆p.e = (mgh) final - (mgh) initial

4 0
3 years ago
The block accelerates down the 30 degree incline at 3m/s2. What is the coefficient of friction of these surfaces
dolphi86 [110]
Fnet = Fg sin 30 - Ff
ma = mg sin 30 - mew Fg cos 30
ma = mg sin 30 - mew mg cos 30
a = g sin 30 - mew gcos30
a - g sin 30 = - mew g cos 30
mew = -(a - g sin30)/(g cos 30)
mew = -(3m/s2 - 9.81sin30)/(9.81 cos 30)
mew = 0.22
8 0
3 years ago
A proton of mass 1.67×10-27 kg is being accelerated along a straight line at 7.01×1015 m/s2 in an accelerator. If the proton has
Masja [62]

Answer:

v_f=7*10^7\frac{m}{s}

Explanation:

The proton is under a linear motion with constant acceleration. So, we use the kinemtic equations to calculate its final speed. We know its acceleration, its initial speed and its traveled distance. Thus, we use the following equation:

v_f^2=v_0^2+2ax\\v_f=\sqrt{v_0^2+2ax}\\v_f=\sqrt{(6.63*10^7\frac{m}{s})^2+2(7.01*10^{15}\frac{m}{s^2})(3.63*10^{-2}m)}\\v_f=7*10^7\frac{m}{s}

5 0
4 years ago
How do various factors affect climent
Svetllana [295]

Answer:

<u>The factors affecting climate are latitude, altitude, land and water distribution, distance from the sea, distance from the sun, prevailing winds and ocean currents, surface covering the land, volcanism, solar constant sunspots, wind direction and nature of mountain chains, mountain barriers.</u>

6 0
3 years ago
Read 2 more answers
If a moon on jupiter has 1/8 the mass of the earth and 1/2 the earth's radius, what is the acceleration of gravity on the planet
dusya [7]

The formula we can use here is:

g = G m / r^2

where g is gravity, G is gravitational constant, m is mass, and r is radius

Since G is constant, therefore we can equate two situations:

g1 m1 / r1^2 = g2 m2 / r2^2

(10 m/s^2) r1^2 / m1 = g2 * (1/2 r1)^2 / (1/8 m1)

<span>g2 = 5 m/s^2</span>

8 0
3 years ago
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