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Airida [17]
4 years ago
6

7. If F1 is the magnitude of the force exerted by the Earth on a satellite in orbit about the Earth and F2 is the magnitude of t

he force exerted by the satellite on the Earth, then which of the following is true?
Physics
2 answers:
natita [175]4 years ago
8 0

Answer:

F1 is equal to F2            

Explanation:

Here

F1 is the gravitational force exerted by the earth on the satellite.

F2 is the gravitational force exerted by the satellite on the earth.

Now these two forces are equal but opposite in nature. This is given by the Third law of motion by Newton. According to this law, when there is force exerted between two objects, one force is balanced the other force which is equal in magnitude and opposite in nature.

Thus the gravitational force of the earth exerted on the satellite is equal to the force exerted by the satellite on the earth.

Hence F1 = F2.

meriva4 years ago
6 0

Answer:

Explanation:

According to the Newton's gravitational law, the force exerted between two bodies obeys the Newton's third law of motion.

it means the force exerted by the earth on the satellite is equal to the force exerted by the satellite on the earth.

So, F1 = F2

The direction of F1 and F2 is opposite top each other.

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Answer:

In the interaction between the bus and the bug, we can call the force "bus pushes bug" the action force. Then the force "bug pushes bus" is the reaction force. Since these forces are a Newton's Third Law action/reaction force pair, they are exactly the same size.

Explanation:

Newtons 3rd law

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3 years ago
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A force of 20N is applied to a 10kg mass on a level frictionless surface. What is the acceleration of the mass
34kurt

Answer:

2m/s^2

Explanation:

f = ma

20 = 10 * a

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8 0
3 years ago
An average human weighs about 650 N. If each of two average humans could carry 1.0 C of excess charge, one positive and one nega
bezimeni [28]

Answer:

Distance, r = 3721.04 meters

Explanation:

It is given that,

Charges on both humans, q_1=q_2=1\ C

Electric force of attraction between them, F = 650 N

We need to find the separation between two humans. It can be solved using the following formula as :

F=\dfrac{kq^2}{r^2}

r=\sqrt{\dfrac{kq^2}{F}}

r=\sqrt{\dfrac{9\times 10^9\times (1)^2}{650}}

r = 3721.04 meters

So, the distance between the humans is 3721.04 meters. Hence, this is the required solution.

5 0
3 years ago
An astronaut holds a rock 100 m above surface of Planet X. The rock is then thrown upwards with a sleek of 15m/s. The rock reach
Gelneren [198K]

Answer:5 m/s^{2}

Explanation:

This problem is related to vertical motion, and the equation that models it is:

y=y_{o}+V_{o}sin\theta t-\frac{1}{2}gt^{2} (1)

Where:

y=0m is the rock's final height

y_{o}=100 m is the rock's initial height

V_{o}=15 m/s is the rock's initial velocity

\theta=90\° is the angle at which the rock was thrown (directly upwards)

t=10 s is the time

g is the acceleration due gravity in Planet X

Isolating g and taking into account sin(90\°)=1 :

g=(-\frac{2}{t^{2}})(y-y_{o}-V_{o}t) (2)

g=(-\frac{2}{(10 s)^{2}})(0 m-100 m-(15 m/s)(10 s)) (3)

g=5 m/s^{2} (4) This is the acceleration due gravity in Planet X

5 0
3 years ago
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