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3 years ago

What is 37/16 as a mixed number?

Mathematics

2 answers:

valentinak56 [21]3 years ago

7 0

The mixed number is 2 1/4

kozerog [31]3 years ago

4 0

37/16

= 2 5/16

........................

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Please help me find how to solve . The area of one is 196 with a side length of 21 in , the other has a side length of 15in

zimovet [89]

Answer:

Area =100 in^2

Step-by-step explanation:

scale factor of the triangles is :15/21=5/7

if two similar shape has a scale factor a/b then the area is a^2:b^2

area of first shape/area of second shape=5/7

x/196=(5)²/(7)²

49x=4900

x=4900/49=100

area=100

check: 100/196=25/49=a^2/b^2

i hope it is right

8 0

4 years ago

Craig has a job waiting tables where he earns $3.15 per hour plus tips. Craig earned $74.67 in tips during his shift yesterday.

oksano4ka [1.4K]

Answer:

3.15x-79.48

i think c:

3 0

3 years ago

How do I calculate the shaded area of this shape ?

TEA [102]

SOLUTION:

We are to calculate the shaded area of the given shape.

CONCEPT:

This is a triangle that a rectangle was cut out from.

To calculate the shaded area of the given shape, we are to find the area of the triangle and then subtract the area of the recangle that was cut out.

$\begin{gathered} \text{Area of Triangle:} \\ A\text{ = }\frac{1}{2}\text{ base }\times\text{ height} \\ \\ A\text{ = }\frac{1}{2}\text{ }\times\text{ 6m }\times7m\text{ } \\ \\ A=21m^2 \end{gathered}$ $\begin{gathered} \text{Area of Rectangle:} \\ A=L\text{ }\times\text{ W } \\ A\text{ = 4m }\times\text{ 2m} \\ A=8m^2 \end{gathered}$

The shaded area = Area of the triangle - Area of the rectangle

$\begin{gathered} \text{Shaded area = 21 m}^2-8m^2 \\ \text{Shaded area = 13 m}^2 \end{gathered}$

3 0

1 year ago

Find the greatest common factor of 8n" and 12m?

alexandr402 [8]

Answer:

Step-by-step explanation:

Factor of 8n = 2x2x2n

Factor of 12m = 2x2x3m

GCF = 2x2 = 4

5 0

4 years ago

Please help? Graph <img src="https://tex.z-dn.net/?f=-3x%5E2%2B12y%5E2%3D84" id="TexFormula1" title="-3x^2+12y^2=84" alt="-3x^2+

mariarad [96]

$-3x^2+12y^2=84$
$12y^2=3x^2+84$
$y^2=\dfrac{x^2}4+7$
$y=\pm\sqrt{\dfrac{x^2}4+7}$

For either square root to exist, you require that $\dfrac{x^2}4+7\ge0$ . This is true for all $x$ , since $\dfrac{x^2}4$ is always non-negative. This means the domain of $y$ as a function of $x$ is all real numbers, or $x\in\mathbb R$ or $(-\infty,infty)$ .

Now, because $\dfrac{x^2}4+7$ is non-negative, and the smallest value it can take on is 7, it follows that the minimum value for the positive square root must be $\sqrt7$ , while the maximum value of the negative root must be $-\sqrt7$ . This means the range is $y\in\mathbb R\setminus(-\sqrt7,\sqrt7)$ , or $|y|\ge\sqrt7$ , or $(-\infty,-\sqrt7]\cup[\sqrt7,\infty)$ .

6 0

4 years ago