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3 years ago

Plz help ASAP 15 points 4. XY is tangent to circle Zat point Y. Xw is tangent to circle Zat point W.

Mathematics

2 answers:

Sladkaya [172]3 years ago

8 0

Answer: 4.8 units

Step-by-step explanation:

mars1129 [50]3 years ago

4 0

9514 1404 393

Answer:

A. 4.8 units

Step-by-step explanation:

Segment ZX can divide the figure into two right triangles. Then angle XZY is 136°/2 = 68°. The tangent relation tells you ...

Tan = Opposite/Adjacent

tan(68°) = XY/r

r = 12/tan(68°) ≈ 4.848 ≈ 4.8

The radius of the circle is about 4.8 units.

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Cuánto es 729 entre 38

riadik2000 [5.3K]

Answer: 19.1842

Step-by-step explanation:

8 0

3 years ago

The first term of an arithmetic sequence is -5, and the tenth term is 13.

Nitella [24]

Answer:

The common difference is 2

Step-by-step explanation:

The formula for an arithmetic sequence is

an = a1+d(n-1)

a1 = -5

a10 = 13

Substituting n=10 a10=13 and a1 =-5

13 = -5 +d (10-1)

13 = -5 +9d

Add 5 to each side

13+5 = -5+5 +9d

18 = 9d

Divide each side by 9

18/9 = 9d/9

2 =d

7 0

3 years ago

Solve for all possible values of x. Show all work.<br> X + 2<br> 2x - 1<br> 3x

pogonyaev

Answer:

a) x+2=0

x= -2

b) 2x-1=0

2x=1

x= 1/2

c) 3x=0

x= 0/3

x=0

6 0

3 years ago

A car drove 330 miles in 6 hours at a constant rate. If the car’s rate of travel slows by 10 mph, what is the new, slower rate o

12345 [234]

Answer:

45 mph

Step-by-step explanation:

Given: Distance travelled= 330 miles

Time taken= 6 h

Lets find out speed of car drove.

Formula; $Speed= \frac{Distance}{time}$

Speed= $\frac{330}{6} = 55\ mph$

∴ Car´s speed is 55 mph.

As we have been informed that car´s rate of travel slows by 10 mph

∴ we have to reduce the current speed of car by 10 mph; $(55-10)= 45\ mph$

The new slower rate of travel is 45 mph.

5 0

3 years ago

what is the density of a sheet of aluminum that has a volume of 328.4 cubic centimeters and a mass of 780 grams

Nata [24]

Answer:

$\large\boxed{density=\dfrac{1950}{821}\ \dfrac{g}{cm^3}\approx2.375\ \dfrac{g}{cm^3}}$

Step-by-step explanation:

$density=\dfrac{mass}{volume}\\\\\text{We have}\\\\mass=780\ g\\volume=328.4\ cm^3\\\\\text{Substitute:}\\\\density=\dfrac{780g}{328.4\ cm^3}=\dfrac{780\cdot10}{328.4\cdot10}\ \dfrac{g}{cm^3}=\dfrac{7800}{3284}\ \dfrac{g}{cm^3}=\dfrac{7800:4}{3284:4}\ \dfrac{g}{cm^3}\\\\=\dfrac{1950}{821}\ \dfrac{g}{cm^3}$

3 0

3 years ago