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erica [24]
3 years ago
7

Putting up 98 points! Will give medal

Chemistry
2 answers:
VladimirAG [237]3 years ago
4 0

A calorimeter contains 500 g of water at 25°C.....

the temperature of the water inside the calorimeter is 39.4°C.....

The specific heat of water is 4.18 J/g-°C.

energy needed to heat the water = specific heat * mass * temp difference

= 4.18 J/g-°C * 500 g * (39.4°C - 25°C)

= 4.18*500*14.4

= 30096J

or approx. 30kJ

Firdavs [7]3 years ago
3 0

Energy=specific heat of water x mass of water x water's temperatures

=4.18x500x(39.4-25)

=30096J

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yes

Explanation:

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5 0
3 years ago
A student inflates a balloon with helium then places it in the freezer. The student should expect
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6 0
3 years ago
about how many times as much volume does a gas occupy compared to the same substance as a liquid or solid under normal condition
7nadin3 [17]

Answer:

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Explanation:

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6 0
3 years ago
Question 22
ruslelena [56]

Answer:

O2, oxygen.

Explanation:

Hello.

In this case, for the undergoing chemical reaction, we need to compute the moles of CO2 yielded by 85 g of CH4 (molar mass = 16 g/mol) and by 320 g of O2 (molar mass 32 g/mol) via the following mole-mass relationships:

n_{CO_2}^{by\ CH_4}=85gCH_4*\frac{1molCH_4}{16gCH_4} *\frac{1molCO_2}{1molCH_4} =5.3molCO_2\\\\n_{CO_2}^{by\ O_2}=320gO_2*\frac{1molO_2}{32gO_2} *\frac{1molCO_2}{2molO_2} =5molCO_2

Considering the 1:2:1 among CH4, O2 and CO2. Therefore, since 320 g of O2 yield the smallest amount of CO2 we infer that the limiting reactant is O2.

Best regards.

5 0
3 years ago
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