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erica [24]
3 years ago
7

Putting up 98 points! Will give medal

Chemistry
2 answers:
VladimirAG [237]3 years ago
4 0

A calorimeter contains 500 g of water at 25°C.....

the temperature of the water inside the calorimeter is 39.4°C.....

The specific heat of water is 4.18 J/g-°C.

energy needed to heat the water = specific heat * mass * temp difference

= 4.18 J/g-°C * 500 g * (39.4°C - 25°C)

= 4.18*500*14.4

= 30096J

or approx. 30kJ

Firdavs [7]3 years ago
3 0

Energy=specific heat of water x mass of water x water's temperatures

=4.18x500x(39.4-25)

=30096J

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