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1 year ago

If the value for ΔS is postive, and the value for ΔH is negative, thr reaction will be

Chemistry

1 answer:

dmitriy555 [2]1 year ago

6 0

It follows that the reaction is spontaneous at high temperatures Option A.

The term ΔS is referred to as the change in the entropy of the system. Now recall that entropy is defined as the degree of disorderliness in a system. If a system is highly disorderly then it means that it has a high entropy. Also, ΔH has to do with the heat change that accompanies a reaction.

We know that both the entropy and the heat change can both either be positive or negative. Now we know that the equation ΔG = ΔH - TΔS can be used to ascertain whether or not a reaction will be spontaneous. If the result is negative, then the reaction will be spontaneous.

As such, when then it follows that the reaction is spontaneous at high temperatures Option A.

Learn more about spontaneous reaction:brainly.com/question/13790391

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During a lab, you heat 1.62 g of a CoCl2 hydrate over a Bunsen burner. After heating, the final mass of the dehydrated compound

sashaice [31]

Answer is: formula of hydrate is CoCl₂· 6H₂O -cobalt(II) chloride hexahydrate
m(CoCl₂· xH₂O) = 1,62 g.
m(CoCl₂) = 0,88 g.
n(CoCl₂) = m(CoCl₂) ÷ M(CoCl₂)
n(CoCl₂) = 0,88 g ÷ 130 g/mol
n(CoCl₂) = 0,0068 mol.
m(H₂O) = 1,62 g - 0,88 g.
m(H₂O) = 0,74 g.
n(H₂O) = m(H₂O) ÷ m(H₂O)
n(H₂O) = 0,74 g ÷ 18 g/mol
n(H₂O) = 0,041 mol.
n(CoCl₂) : n(H₂O) = 0,0068 mol : 0,041 mol.
n(CoCl₂) : n(H₂O) = 1 : 6.

8 0

3 years ago

NEED HELP I WILL RATE BRAINLIEST!!!!

dlinn [17]

Hope this helps!! You were correct for Question 9 but incorrect for Question 10. Yes, the value comes out to be 62.4 kJ but watch out for your signs! It is definitely a positive number. Therefore, you have to consider your other choices. When I converted the 62.4 kJ to J, I found an option that matches my answer.

5 0

3 years ago

Compounds A and B are constitutional isomers (same molecular formula but

Naily [24]

Answer:

Trimethylacetaldehyde

Explanation:

For the unknow compound we have a molar mass of 86 g/mol. We have an even value for the mass, so the compound does not have nitrogen and we can have several posibilities:

A) $C_3H_2O_3$

B) $C_4H_6O_2$

C) $C_5H_1_0O$

D) $C_6H_1_4$

If we check the IR info a signal in 1730 cm-1 appears, this indicates that we have an oxo group (C=O). So, the D option can be discarded. The groups that can have the oxo group are: Carboxylic acids, Ketones and aldehydes.

We don have a signal in 3000 cm-1, so the carboxylic acid can be discarded. Now, is we check the info for the 1H NMR we only have 2 signals. If we only have 2 we will have a very symmetric compound.

By trial an error the find the compound Trimethylacetaldehyde (Figure 1).

3 0

3 years ago

The graph below shows a reaction to which a catalyst has been added. How would the graph be different if it showed the same reac

Lady bird [3.3K]

Answer:

a. the width of region 2 would be smaller

4 0

2 years ago

A student is investigating the pH of a substance. The pH of the unknown substance is 5.4. Which of the following substances is t

zimovet [89]

Answer:

Substance A.

Explanation:

pH is a measure of the concentration of H₃O⁺ ions in a solution.

It is defined as:

$pH=\log \dfrac{1}{[H_3O^+]}=-\log [H_3O^+]$

For the given substances

Sustance [H₃O⁺] pH = - log [H₃O⁺]

A 4×10⁻⁶ -log (4×10⁻⁶) = 5.4 ← answer

B 6×10⁻⁷ -log (6×10⁻⁷) = 6.2

C error - - - - - -

D 1.3×10⁻¹ -log (1.3×10⁻¹) = 0.89

Thus, the unknown substace most likely is A.

3 0

3 years ago