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madreJ [45]
3 years ago
5

Susan needs to measure and heat the chemical she wants to use in an experiment with a graduated cylinder. Which graduated cylind

er is suitable for use?
A) Plastic cylinder
B) Glass cylinder
C) Metal cylinder
Chemistry
2 answers:
Brut [27]3 years ago
6 0
I think the best answer from the choices listed above is option B. The best graduated cylinder for this case is the glass cylinder. A metal cylinder is not possible because you cannot measure really since metals are not transparent. A plastic cylinder cannot also be used since the substance should be heated for the experiment.
Fofino [41]3 years ago
6 0

Answer:

Glass cylinders

Explanation:

Glass cylinders

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Hydrazine (N2H4), a rocket fuel , reacts with oxygen to form nitrogen gas and water vapor. The reaction is represented with the
Serggg [28]

85.33 grams of hydrazine is needed for the reaction.

Rocket fuel contains the reaction between hydrazine and oxygen to break and form nitrogen and water vapour along with steam as it is an exothermic reaction.

<h3>How to calculate the hydrazine amount?</h3>

The reaction can be shown as:

\rm N_{2}H_{4}(l) + O_{2}(g) \rightarrow N_{2}(g) + 2H_{2}O(g)

From the periodic chart, it can be said that:

  • Mass of nitrogen = 14 gm
  • Mass of oxygen = 16 gm
  • Mass of hydrogen = 1 gm

The molar mass of hydrazine will be:

\begin{aligned} \rm Molar \;mass \;of \rm \;N_{2}H_{4}&= 2(14) + 4(1) \\\\&= 32 \;\rm grams\end{aligned}

Mass of water:

\begin{aligned}&= 2(1) + 16 \\\\&= 18 \;\rm grams\end{aligned}

From the reaction, it can be said that,

1 mole of \rm N_{2}H_{4} = 2 moles of \rm H_{2}O

32 grams of \rm N_{2}H_{4}  = ? grams of water

\begin{aligned}\text{Gram of water} &= 18 \times 2\\\\&= 36 \;\rm gm\end{aligned}

So, for 96 gm of water the hydrazine produced will be,

\begin{aligned}\text{mass of }\rm N_{2}H_{4} &= \dfrac{96 \times 32}{36}\\\\&= 85.3334 \;\rm grams \end{aligned}

Therefore, 85.33 grams of hydrazine is needed for the reaction.

Learn more about rocket fuel here:

brainly.com/question/10179270

7 0
2 years ago
For the following reactions, write a balanced equation using half-reactions and calculate the voltage to be expected.
Iteru [2.4K]

a) 2Na(s) +2H_2O(I)→ 2Na^+(aq) + OH^-(aq)+ H_2(g)

b) 2Ag (s) +2H^(aq) → 2 Ag^+ (aq) +H_2(g)

<h3>What are half-reactions?</h3>

The half-reaction method is a way to balance redox reactions. It involves breaking the overall equation down into an oxidation part and a reduction part.

a)

2Na(s) +2H_2O(I)→ 2Na^+(aq) + OH^-(aq)+ H_2(g)

E^0 cell = E^0 (reduction)  - E^0 (oxidation)

= E^0(\frac{H_2O}{H_2}, OH^-) -E^0(Na^+/Na)

= -0.83 - (-2.71) =1.88V

b)

2Ag (s) +2H^(aq) → 2 Ag^+ (aq) +H_2(g)

E^0cell= E^0(H^+/H_2) -E^0(Ag^+/Ag)

E^0cell=-0. - (0.8) =-0.8V

Learn more about the half-reactions here:

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8 0
2 years ago
The density of ethanol, C2H5OH, is 0.789 g/mL. How many milliliters of ethanol are needed to produce 15.0 g of CO2 via a combust
bearhunter [10]

<u>The answer is </u><u>9.94 ml.</u>

<h3>What is density?</h3>
  • Density is a word we use to describe how much space an object or substance takes up (its volume) in relation to the amount of matter in that object or substance (its mass).
  • Another way to put it is that density is the amount of mass per unit of volume. If an object is heavy and compact, it has a high density.

Given,

        The density of ethanol, C2H5OH = 0.789 g/mL

n (CO_{2} ) = \frac{m}{M}  = \frac{15G}{44 g/mol} } = 0.341 mol;

n ( C_{2} H_{2} OH) = \frac{n (CO_{2}) }{2}  = \frac{0.341}{2}  = 0.1705  mol;

m (C_{2} H_{2} OH) = 0.1705 mol * 46  g/ mol = 7.843 g

V (C_{2} H_{2} OH ) = \frac{7.843}{0.789} = 9.94 ml.

Therefore, the answer is 9.94 ml

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<u>The complete question is -</u>

If the density of ethanol, C2H5OH, is 0.789 g/mL. How many milliliters of ethanol are needed to produce 15.0 g of CO2 according to the following chemical equation?

C2H5OH(l) + 3 O2(g) → 2 CO2(g) + 3 H2O(l)

5 0
2 years ago
N a rate law, the rate constant, k, depends on which condition?
Tanya [424]
In a rate law constant K(kt), Depends only on Temperature.


Answer: would be Temperature, if temperature is constant, then rate law is constant.





Hope that helps!!!

6 0
4 years ago
? Question
mr_godi [17]

A is the answer

In an ozone molecule, the three atoms must be connected, so there must at least be a single bond between them. Place

dots in pairs around the oxygen atoms until each oxygen atom has eight valence electrons, starting with the atoms on the

outside and doing the central atom last if there are enough. Do not exceed the total number of valence electrons

identified in part A. Remember that the dashes between the oxygen atoms, which represent single bonds, each indicate

the presence of two valence electrons

6 0
3 years ago
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