Answer:
It remains the same
Explanation:
The law of conservation of mass states that, during a chemical reaction, the total mass of the products must be equal to the total mass of the reactants.
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D = M/V = 76g / 22ml = 3.4g/ml
Half ~ D = 38g / 11ml = 3.4g/ml
Even if the object you had was cut in half, it’s density would remain the same.
Answer:
Well,
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Pb(NO3)2 (aq) + 2 NaI (aq) --> PbI2 (s) + 2 NaNO3 (aq)
Starting with with 200.0 grams of Pb(NO3)2 and 120.0 grams of NaI:
A. What is the limiting reagent?
B. How many grams of PbI2 is theoretically formed?
C. How many grams of the excess reactant remains?
D. If 48 grams of NaNO3 actually formed in the reaction, what is the percent yield of this reaction?