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3 years ago

Classify each chemical reaction:

Chemistry

1 answer:

I am Lyosha [343]3 years ago

5 0

Answer:

1) combustion

2) double replacement

3) combination

4) combustion

Explanation:

The combustion of a compound refers to the reaction of that compound with oxygen to produce heat and light. In reactions (1) and (4) above, ethanol and methane reacted with oxygen to yield carbon dioxde and water. This is a combustion reaction.

Reaction(2) is a double replacement reaction because the both cations exchange their anion partners in the product.

Reaction (3) is a combination reaction. It involves the joining of two elements to form a new compound.

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inessss [21]

Answer:

1. The energy intensity from the ruler going through the air

2. This one is pretty simple, you can add or take away things. This question is just asking you to list sounds from high pitch, to lowest pitch. Here are mine:

Timer

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Typing

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Explanation:

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2 years ago

What is the reason for attainment of equilibrium?

Shtirlitz [24]

Answer:

When a reversible reaction happens in a closed container, it reaches a dynamic equilibrium . At equilibrium: the forward and backward reactions are still happening. the forward and backward reactions have the same rate of reaction

Explanation:

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3 years ago

Carbon dioxide (CO2) is a gaseous compound. Calculate the percent composition of this compound. Answer using three significant f

Tamiku [17]

Carbon dioxide is a gaseous molecule made up of the elements, C and O. Each mole of carbon dioxide has one mole C and two mole oxygen atoms.

Molar mass of carbon dioxide ( $CO_{2}$ )= $(1 * 12.01\frac{g}{mol}) +(2* 16\frac{g}{mol})=44.01\frac{g}{mol}$

Percentage by mass of carbon = $\frac{(1*12.01\frac{g}{mol}) }{44.01\frac{g}{mol} } *100=27.3%$

Percentage by mass of oxygen = $\frac{(2*16\frac{g}{mol})}{44.01\frac{g}{mol} } *100=72.7%$

Therefore C is 27.3 % and O is 72.7 % by mass in 1 mol CO $_{2}$

7 0

4 years ago

Read 2 more answers

What mass of calcium chloride is needed to prepare 2.657 L of a 1.56 M solution?

inna [77]

Answer:

459.126 grams of calcium chloride is needed to prepare 2.657 L of a 1.56 M solution

Explanation:

Molarity is a measure of the concentration of a solute in a solution that indicates the amount of moles of solute that appear dissolved in one liter of the mixture. In other words, molarity is the number of moles of solute that are dissolved in a given volume.

The Molarity of a solution is determined by the following expression:

$Molarity=\frac{number of moles of solute}{volume}$

Molarity is expressed in units $\frac{moles}{liter}$

In this case:

Molarity: 1.56 M= 1.56 $\frac{moles}{liter}$
Number of moles of calcium chlorine= ?
Volume= 2.657 liters

Replacing:

$1.56 M=\frac{Number of moles of calcium chlorine}{2.657 liters}$

Solving:

Number of moles of calcium chlorine= 1.56 M* 2.657 liters

Number of moles of calcium chlorine= 4.14 moles

In other side, you know:

Ca: 40 g/mole
Cl: 35.45 g/mole

Then the molar mass of the calcium chloride CaCl₂ is:

CaCl₂= 40 g/mole + 2* 35.45 g/mole= 110.9 g/mole

Now it is possible to apply the following rule of three: if in 1 mole there is 110.9 g of CaCl₂, in 4.14 moles of the compound how much mass is there?

$mass=\frac{4.14 moles*110.9g}{1 mole}$

mass= 459.126 g

<u><em>459.126 grams of calcium chloride is needed to prepare 2.657 L of a 1.56 M solution</em></u>

3 0

3 years ago

Calculate the ΔHrxn for the following

Vesnalui [34]

Answer:

2 NO (g) → N2 (g) + O2 (g)

2 NOCl (g) → 2 NO (g) + Cl2 (g)

____________________________

2NOCl (g) ⟶ N2 (g) + O2 (g) + Cl2 (g)

ΔH = [90.3 kJ x 2 x -1] + [-38.6 kJ x -1 x 2] = -103.4 kJ

The ΔH for the reaction is -103.4 kJ

6 0

3 years ago