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Softa [21]
3 years ago
7

____ CH4 + ____ O2 ____ CO2 + ____ H2O Balance the equation

Chemistry
2 answers:
solong [7]3 years ago
4 0

Explanation:

ch4+202 = co2+2H20

1 c on both side so balance

there are 4 h on one side but 2 on the other side so you need to add a 2 so 4 on both sides

the O have 4 both sides so balanced

alisha [4.7K]3 years ago
4 0

Answer:

\huge \boxed{\mathrm{CH_4+ 2O_2 \Rightarrow CO_2 +2 H_2O}}

\rule[225]{225}{2}

Explanation:

\sf CH_4+ O_2 \Rightarrow CO_2 + H_2O

Balancing the Hydrogen atoms on the right side,

\sf CH_4+ O_2 \Rightarrow CO_2 +2 H_2O

Balancing the Oxygen atoms on the left side,

\sf CH_4+ 2O_2 \Rightarrow CO_2 +2 H_2O

\rule[225]{225}{2}

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Everyone in Mrs. Blaylock's science class must perform an experiment for the science fair this year. To begin this process, Mrs.
sergey [27]

Answer:

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Explanation:

Science or scientific investigations deal with objective phenomena; this is phenomena which can be described by using objective measurements.

The effect of the position of the Sun, moons, planets and stars on a person's personality and daily behavior patterns is not a scientific question because none scientific field deals with that kind of questions.

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6 0
3 years ago
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almond37 [142]
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4 0
3 years ago
What is the mole fraction of NaOH in
insens350 [35]

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8 0
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Small quantities of hydrogen and helium gas at the same temperature are released simultaneously at one end of a laboratory. Stat
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4 0
3 years ago
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Given the balanced chemical equation for combustion of propane:

C_{3}H_{8}+5O_{2}-->3CO_{2}+4H_{2}O

Moles of propane C_{3}H_{8}=3.6 mol

Propane is the limiting reactant as the other reactant oxygen is said to be present in excess.

Amount of products formed would depend on the moles of limiting reactant.

Mole ratio of water to propane as per the balanced chemical equation

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Calculating the moles of water produced from 3.6 mol propane:

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Theoretical yield of water = 14.4 mol

Actual yield = 12 mol

Percent yield = \frac{ActualYield}{TheoreticalYield}*100

                      = \frac{12 mol}{14.4 mol}*100=83.3%

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3 years ago
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