Answer:
ee = 96%
Explanation:
Enantiomeric excess, ee, is a way to express a mixture that is not enantiomerically pure. It is defined as 100 times the ratio between the differences of amounts of enantiomers and the total amunt. that is:
ee = |A-B|/ A+B * 100
ee = |98%-2%| / 98+2 * 100
<h3>ee = 96%</h3>
In a distillation model, it is better to let the cold water enter the bottom of the condenser and exit at the top because this can lead to a better cooling effect.
When water enters from the bottom, they will stay longer in the condenser, thus the vapor in the condenser can be cooled back into liquid faster.
In addition, this method can also save the amount of water used, since they water can stay longer in the condenser.
Answer:
The density of helgas sample is 17.8 g/cm³.
Explanation:
Given that,
Mass of sample of Rowena = 5 gram
Density = 8.9 g/cm³
Mass of sample of helga = 10 gram
We need to calculate the volume of sample
Using formula of volume

Where, m = mass
= density
Put the value into the formula


We need to calculate the density of helgas sample
Using formula of density

Where, m = mass
V = volume
Put the value into the formula


Hence, The density of helgas sample is 17.8 g/cm³.
Im so sorry i dont understand this i wish i could help....