Answer:
Step-by-step explanation:
Taking the terms one at a time,
Adding the terms, you have;
Hope it helps!
I'm out!
I have a that is 1000 milligrams and I suppose to take a 200 milligrams how many milliliters will I take?
1 answer:
You might be interested in
9514 1404 393
Answer:
5) 729, an=3^n, a[1]=3; a[n]=3·a[n-1]
6) 1792, an=7(4^(n-1)), a[1]=7; a[n]=4·a[n-1]
Step-by-step explanation:
The next term of a geometric sequence is the last term multiplied by the common ratio. (This is the basis of the recursive formula.)
The Explicit Rule is ...
for first term a₁ and common ratio r.
The Recursive Rule is ...
a[1] = a₁
a[n] = r·a[n-1]
__
5. First term is a₁ = 3; common ratio is r = 9/3 = 3.
Next term: 243×3 = 729
Explicit rule: an = 3·3^(n-1) = 3^n
Recursive rule: a[1] = 3; a[n] = 3·a[n-1]
__
6. First term is a₁ = 7; common ratio is r = 28/7 = 4.
Next term: 448×4 = 1792
Explicit rule: an = 7·4^(n-1)
Recursive rule: a[1] = 7; a[n] = 4·a[n-1]
Answer:
5) DE = 7 units and DF = 4 units
6) ST = 8 units
8) x ≤ -3 and x ≥ 3
Step-by-step explanation:
<u>Information from Parts 1-4:</u>
- A = (3, 0) and C = (-3, 0)
Points A and D are the <u>points of intersection</u> of the two functions.
To find the x-values of the points of intersection, equate the two functions and solve for x:
Apply the zero-product property:
From inspection of the graph, we can see that the x-value of point D is <u>negative</u>, therefore the x-value of point D is x = -4.
To find the y-value of point D, substitute the found value of x into one of the functions:
Therefore, D = (-4, 7).
The length of DE is the difference between the y-value of D and the x-axis:
⇒ DE = 7 units
The length of DF is the difference between the x-value of D and the x-axis:
⇒ DF = 4 units
<h3><u>Part (6)</u></h3>To find point S, substitute the x-value of point T into function g(x):
Therefore, S = (4, 7).
The length ST is the difference between the y-values of points S and T:
Therefore, ST = 8 units.
<h3><u>Part (7)</u></h3>The given length of QR (⁴⁵/₄) is the difference between the functions at the same value of x. To find the x-value of points Q and R (and therefore the x-value of point M), subtract g(x) from f(x) and equate to QR, then solve for x:
Apply the zero-product property:
As the x-value of points M, Q and P is negative, x = -³/₂.
Length OM is the difference between the x-values of points M and the origin O:
Therefore, OM = ³/₂ units.
<h3><u>Part (8)</u></h3>The values of x for which g(x) ≥ 0 are the values of x when the parabola is above the x-axis.
Therefore, g(x) ≥ 0 when x ≤ -3 and x ≥ 3.