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sesenic [268]
3 years ago
11

A period of one year on Earth is the time it takes Earth to

Physics
1 answer:
Kazeer [188]3 years ago
7 0

D make one revolution around the sun hope this helps

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Lunar eclipse
vichka [17]

Answer:

Hey

Your answer would be

The moon is not visible

due to Earth's shadow=lunar eclipse

The sun is not visible due

to the moon=solar eclipse

The moon is on the side of

Earth opposite the sun=new moon

The moon and sun are on

the same side of Earth=full mon

4 0
3 years ago
1) An ac source of period T and maximum voltage V is connected to a single unknown ideal element that is either a resistor, and
Lady_Fox [76]

Answer: Capacitor

Explanation:

Given the following ;

At time, t = T/4 ; I = 0

At time, t = T/2 ; I = - Imax

Where T = period

We can confirm what the unknown element is by using the relation, such that the parameters satisfy the stated condition ;

Recall;

I = Iosin(wt + π/2) [for CAPACITOR]

w = 2π/T

At t = T/4

I = Iosin(2π/T(T/4) + π/2)

I = Iosin(π/2 + π/2)

I = Iosin(0)

I = 0

At t = T/2

I = Iosin(2π/T(T/2) + π/2)

I = Iosin(π + π/2)

I = Iosin(0)

I = Iosin(3π/2)

I = Iosin(540/2)

I = Iosin(270)

I = -Io

Note : Io = Imax

Both conditions are met, Hence, the unknown element is a CAPACITOR.

6 0
3 years ago
Two skaters stand facing each other. One skater's mass is 60 kg, and the other's
jeyben [28]

Answer:

v' = 2.4 m/s

Explanation:

Given that,

Mass of one skater, m = 60 kg

Mass of the other's skater, m' = 60 kg

The two skaters push off each other. After the push, the smaller  skater has a velocity of 3.0 m/s.

When there is no external force acting on a system, the momentum remains conserved. It means initial momentum is equal to the final momentum. Let v' is the velocity of the larger skater.

mv = m'v'

v'=\dfrac{mv}{m'}\\\\v'=\dfrac{60\times 3}{75}\\\\v'=2.4\ m/s

So, the velocity of the larger skater is 2.4 m/s.

3 0
3 years ago
A uranium-238 atom can break up into a thorium-234 atom and a particle called an alpha particle, αα-4. The numbers indicate the
alexdok [17]

Answer: E = 5.80*10^-13 J

Explanation:

Given

We use the law of conservation of momentum to solve this

Momentum before breakup = momentum after breakup

0 = m1v1 + m2v2

0 = 238m * -2.2*10^5 + 4m * v2

0 = -523.6m m/s + 4m * v2

v2 * 4m = 523.6m m/s

v2 = 523.6 m m/s / 4m

v2 = 130.9*10^5 m/s

v2 = 1.31*10^7 m/s

Using this speed in the energy equation, we have

E = 1/2m1v1² + 1/2m2v2²

E = 1/2 * (238 * 1.66*10^-27) * -2.2*10^5² + 1/2 * (4 * 1.66*10^-27) * 1.31*10^7²

E = [1/2 * 3.95*10^-25 * 4.84*10^10] + [1/2 * 6.64*10^-27 * 1.716*10^14]

E = (1/2 * 1.911*10^-14) + (1/2 * 1.139*10^-12)

E = 9.56*10^-15 + 5.7*10^-13

E = 5.80*10^-13 J

3 0
3 years ago
A rhinoceros is at the origin of coordinates at time t1 = 0. for the time interval from t1 = 0 to t2 = 21.5 s, the rhino's avera
Ainat [17]
A) The rhino's average velocity on the x-axis is v_x=-3.8 m/s. The position x after time t=21.5 s can be found by using the relationship:
x=x_0 + v_x t=0+(-3.8 m/s)(21.5 s)=-81.7 m
where we used x_0=0 as the x-position at time t=0, since the rhino was at the origin.

SImilarly, the average velocity on the y-axis is v_y=+4.5 m/s, and the y-position after time t=21.5 s can be found by using:
y=y_0+(+4.5 m/s)(21.5 s)=+96.8 m
where we used y_0=0 since the the rhino was at the origin at time t=0.

b) The distance of the rhino from the origin can be calculated by calculating the resultant of the displacement of the rhino on both axes:
d= \sqrt{x^2+y^2}= \sqrt{(-81.7 m)^2+(96.8m)^2}=126.7 m
6 0
3 years ago
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