Answer:
Hey
Your answer would be
The moon is not visible
due to Earth's shadow=lunar eclipse
The sun is not visible due
to the moon=solar eclipse
The moon is on the side of
Earth opposite the sun=new moon
The moon and sun are on
the same side of Earth=full mon
Answer: Capacitor
Explanation:
Given the following ;
At time, t = T/4 ; I = 0
At time, t = T/2 ; I = - Imax
Where T = period
We can confirm what the unknown element is by using the relation, such that the parameters satisfy the stated condition ;
Recall;
I = Iosin(wt + π/2) [for CAPACITOR]
w = 2π/T
At t = T/4
I = Iosin(2π/T(T/4) + π/2)
I = Iosin(π/2 + π/2)
I = Iosin(0)
I = 0
At t = T/2
I = Iosin(2π/T(T/2) + π/2)
I = Iosin(π + π/2)
I = Iosin(0)
I = Iosin(3π/2)
I = Iosin(540/2)
I = Iosin(270)
I = -Io
Note : Io = Imax
Both conditions are met, Hence, the unknown element is a CAPACITOR.
Answer:
v' = 2.4 m/s
Explanation:
Given that,
Mass of one skater, m = 60 kg
Mass of the other's skater, m' = 60 kg
The two skaters push off each other. After the push, the smaller skater has a velocity of 3.0 m/s.
When there is no external force acting on a system, the momentum remains conserved. It means initial momentum is equal to the final momentum. Let v' is the velocity of the larger skater.
mv = m'v'

So, the velocity of the larger skater is 2.4 m/s.
Answer: E = 5.80*10^-13 J
Explanation:
Given
We use the law of conservation of momentum to solve this
Momentum before breakup = momentum after breakup
0 = m1v1 + m2v2
0 = 238m * -2.2*10^5 + 4m * v2
0 = -523.6m m/s + 4m * v2
v2 * 4m = 523.6m m/s
v2 = 523.6 m m/s / 4m
v2 = 130.9*10^5 m/s
v2 = 1.31*10^7 m/s
Using this speed in the energy equation, we have
E = 1/2m1v1² + 1/2m2v2²
E = 1/2 * (238 * 1.66*10^-27) * -2.2*10^5² + 1/2 * (4 * 1.66*10^-27) * 1.31*10^7²
E = [1/2 * 3.95*10^-25 * 4.84*10^10] + [1/2 * 6.64*10^-27 * 1.716*10^14]
E = (1/2 * 1.911*10^-14) + (1/2 * 1.139*10^-12)
E = 9.56*10^-15 + 5.7*10^-13
E = 5.80*10^-13 J
A) The rhino's average velocity on the x-axis is

. The position x after time t=21.5 s can be found by using the relationship:

where we used

as the x-position at time t=0, since the rhino was at the origin.
SImilarly, the average velocity on the y-axis is

, and the y-position after time t=21.5 s can be found by using:

where we used

since the the rhino was at the origin at time t=0.
b) The distance of the rhino from the origin can be calculated by calculating the resultant of the displacement of the rhino on both axes: