A period of one year on Earth is the time it takes Earth to

If you pull a wool sweater over your head, you will often end up with a wild hairdo. Your hair is hard to comb and wants to stan

Sergio [31]

Becasue when you rubbed your hair while you were putting on your sweater it caused it to rub against together causing electricity thingy lol. and thats why your hair goes straigh tup.

5 0

3 years ago

On a tiny scale, what happens to an initially neutral object’s mass when it gains a net positive charge through the exchange of

Advocard [28]

Answer:

On a tiny scale, what happens to an initially neutral object’s mass when it gains a net positive charge through the exchange of electrons? (the mass will decrease by a very small factor)

(b) What happens to the mass of an initially neutral object when it gains a net negative charge through the exchange of electrons? (The mass will increase by a very small factor)

Explanation:

(a) On a tiny scale, what happens to an initially neutral object’s mass when it gains a net positive charge through the exchange of electrons? (the mass will decrease by a very small factor)

The mass of an atom is given by the sum of the masses of the protons, neutrons and electrons. Electrons has lower mass than protons and neutrons, so they have a minor contribution to the total mass of the atom.

When an object is electrically neutral it means that it has the same number of protons and electrons. For the case of an object positively charged, the rate of protons is greater than the number of electrons. That means that atom lose electrons so the mass will decrease in a very small factor.

(b) What happens to the mass of an initially neutral object when it gains a net negative charge through the exchange of electrons? (The mass will increase by a very small factor)

For the case when the object is negatively charged, it means that the atom gains electrons from another object, leading to the conclusion that the mass of the atom will increase in a very small factor.

Key values:

Electron mass: 9.1095×10⁻³¹ Kg

Proton mass: 1.67261×10⁻²⁷ Kg

Neutron mass: 1.67492×10⁻²⁷ Kg

5 0

3 years ago

Pls help I will mark brainliest

irina1246 [14]

B, a disurbance would make it unstable and affect the center of mass, which would then affect the equilibrium.

4 0

3 years ago

At a distance of 8 m, the sound intensity of one speaker is 66 dB. If we were to place 3 speakers in a circle of radius 8 m, wha

ludmilkaskok [199]

Answer:

dβ = 70. 77 dβ

Explanation:

The intensity of sound in decibels is

dβ = 10 log I/I₀

let's look for the intensity of this signal

I / I₀ = 10 dβ/10

I / I₀ = 3.981 10⁶

the threshold intensity of sound for humans is I₀ = 1 10⁻¹² W / m²

I = 3.981 10 ⁶ 1 10⁻¹²

I = 3,981 10⁻⁶ W / m²

It is indicated that 3 cornets are placed in the circle, for which total intensity is

I_total - 3 I

I_total = 3 3,981 10⁻⁶

I_total = 11,943 10⁻⁶ W / m²

let's reduce to decibels

dβ = 10 log (11,943 10⁻⁶/1 10⁻¹²)

dβ = 10 7.077

dβ = 70. 77 dβ

3 0

3 years ago

During what time interval was the object traveling most quickly?

anygoal [31]

ANSWER

0s to 3s

EXPLANATION

To find the time interval where the object was traveling more quickly, we have to find the velocity of the object during each interval.

From a position-time graph, we can obtain the velocity of the object from the slope of the graph in each interval. To find those slopes, we just have to divide the vertical difference by the time interval.

The interval from 0s to 3s:

$v=\frac{7-3}{0-3}=-\frac{4}{3}m/s$

The interval from 3s to 5s and the interval from 7s to 8s have a horizontal line, so the slope is zero and therefore the velocity is zero - meaning that the object was not moving during these periods.

The interval from 5s to 7s,

$v=\frac{5-3}{7-5}=\frac{2}{2}=1m/s$

And the interval from 8s to 12s,

$v=\frac{0-5}{12-8}=-\frac{5}{4}m/s$

Two of these three velocities are negative. Negative velocity indicates that the object is moving backward.

From these velocities, the greatest one, in absolute value, is the one between 0s to 3s. During this interval, the object is moving backward but at the greatest velocity.

3 0

1 year ago