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sesenic [268]
3 years ago
11

A period of one year on Earth is the time it takes Earth to

Physics
1 answer:
Kazeer [188]3 years ago
7 0

D make one revolution around the sun hope this helps

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The current supplied by a battery as a function of time is I(t) = (0.88 A) e^(-t*6 hr). What is the total number of electrons tr
Degger [83]

Answer:

e. 1.2 x 10²³

Explanation:

According to the problem, The current equation is given by:

I(t)=0.88e^{-t/6\times3600s}

Here time is in seconds.

Consider at t=0 s the current starts to flow due to battery and the current stops when the time t tends to infinite.

The relation between current and number of charge carriers is:

q=\int\limits {I} \, dt

Here the limits of integration is from 0 to infinite. So,

q=\int\limits {0.88e^{-t/6\times3600s}}\, dt

q=0.88\times(-6\times3600)(0-1)

q = 1.90 x 10⁴ C

Consider N be the total number of charge carriers. So,

q = N e

Here e is electronic charge and its value is 1.69 x 10⁻¹⁹ C.

N = q/e

Substitute the suitable values in the above equation.

N= \frac{1.9\times10^{4} }{1.69\times10^{-19}}

N = 1.2 x 10²³

8 0
3 years ago
If the 50-kg crate starts from rest and achieves a velocity of v = 4 m/s
Kay [80]

Answer:

P = 227 N

Explanation:

Assuming the crate is on horizontal ground and subject to a horizontal force.

F = ma

P - μmg = ma

P = m(a + μg)

P = m(v²/2s + μg)

P = 50(4²/(2(5))+ 0.3(9.8))

P = 227 N

6 0
3 years ago
The electric potential at the surface of a charged conductor _______.
frez [133]

Answer:

The electric potential at the surface of a charged conductor<u> is always such that the potential is zero at all points inside the conductor.</u>

Explanation:

Each point on the surface of a balanced charged conductor has the same electrical potential.

The surface on any charged conductor in electrostatic equilibrium is an equipotential surface. Since the electric field is equal to zero inside the conductor, the electric potential at any point inside and on the surface is equivalent to its value.

6 0
3 years ago
A mover does 422 J of work pushing a crate 8.39 m. How much force did he exert?
kicyunya [14]

Answer:

50.3N

Explanation:

Work done = force x distance

422J. = force x 8.39m

÷8.39 both side to get force

Force is 50.3N to 1 d.p.

Check:

50.3 x 8.39=422.017J

Same as 422J to 1 d.p

4 0
2 years ago
Read 2 more answers
PLEASE HELP ME WITH THIS ONE QUESTION
Vlad [161]

Answer: 7.95^{\circ}C

Explanation:

Given

Mass of water is m_1=1\ kg

mass of ice is m_2=0.1\ kg

Latent heat of fusion L=3.33\times 10^5\ kJ/kg

The heat capacity of water is c_{w}=4186\ J/kg^{\circ}C

Suppose water is at  T^{\circ} C  and it reaches to 0^{\circ}C to melt the ice

the heat released by water must be equivalent to heat absorbed by the ice

\therefore \quad m_1c_w(T-0)=m_2\times L\\\Rightarrow 1\times 4186\times T=0.1\times 3.33\times 10^5\\\Rightarrow T=7.95^{\circ}C

6 0
2 years ago
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