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3 years ago

How much time is needed to push a 5,000 N car 50 meters if you are using a machine with a power of 4,500 W?

Physics

1 answer:

Dafna1 [17]3 years ago

8 0

Answer:

55.56

Explanation:

5000N * 50 = 250000/4500= 55.55555555 or 55.56

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physics major is cooking breakfast when he notices that the frictional force between the steel spatula and the Dry Steel frying

givi [52]

Answer:0.667 N

Explanation:

Given

It is noticed that Frictional Force is 0.2 N

Coefficient of kinetic Friction $\mu _k=0.3$

We know Friction Force is given by

$f_r=\mu _k\times Normal\ reaction$

therefore

$0.2=\mu _k\times N$

$0.2=0.3\cdot N$

$N=\frac{0.2}{0.3}$

$N=0.667 N$

8 0

3 years ago

A mass of 0.34 kg is fixed to the end of a 1.4 m long string that is fixed at the other end. Initially at rest, he mass is made

frozen [14]

At time $t$ seconds, the mass has angular speed

$\omega = \left(3.31\dfrac{\rm rad}{\mathrm s^2}\right) t$

and hence linear speed

$v = (1.4\,\mathrm m) \omega = (1.4\,\mathrm m) \left(3.31\dfrac{\rm rad}{\mathrm s^2}\right) t$

After 8 s, its linear speed is

$v = (1.4\,\mathrm m) \left(3.31\dfrac{\rm rad}{\mathrm s^2}\right) (8\,\mathrm s) = 37.072 \dfrac{\rm m}{\rm s} \approx 37 \dfrac{\rm m}{\rm s}$

and has centripetal acceleration with magnitude

$a = \dfrac{v^2}{1.4\,\rm m} \approx 981.667\dfrac{\rm m}{\mathrm s^2} \approx 980 \dfrac{\rm m}{\mathrm s^2}$

To maintain this linear speed, by Newton's second law the required centripetal force should have magnitude

$F = (0.34\,\mathrm{kg}) a \approx 333.767\,\mathrm N \approx \boxed{330 \,\mathrm N}$

5 0

2 years ago

a wire is carrying a 2.45 A current. at what distance from the wire is the magnetic field 1.00x10^-6t

balu736 [363]

Answer:

0.49m

Explanation:

So you need to change the original equation for finding fields to find distance, and then just plug in the numbers

Which equals 0.49meters

Also it was right on Acellus :)

Hope this helps

5 0

3 years ago

What volume of h2 gas (in l), measured at 756 mmhg and 90 ∘c, is required to synthesize 23.0 g ch3oh?

Naddika [18.5K]

First let us calculate for the moles of CH3OH formed:

moles CH3OH = 23 g / (32 g / mol) = 0.71875 mol

We see that there are 2 moles of H2 per mole of CH3OH, so:

moles H2 = 0.71875 mol * 2 = 1.4375 mol

Assuming ideal gas behaviour, we use the formula:

PV = nRT

V = nRT / P

V = 1.4375 mol * (62.36367 L mmHg / mol K) * (90 + 237.15 K) / 756 mm Hg

<span>V = 43.06 Liters</span>

6 0

3 years ago

What's the difference in a balanced force in an unbalanced force

AlekseyPX

There's no such thing as one balanced force or one unbalanced force.

If ALL of the forces in a GROUP of forces acting on the same object
all add up to zero, then we say that the GROUP of forces is balanced.

If they don't, then the GROUP of forces is unbalanced.

Two or more forces can be balanced or unbalanced.
One force can't.

7 0

3 years ago