A transverse wave and a longitudinal wave.
Transverse:wave particles move at medium speed in perpendicular to the direction that the waves move
Longitudinal:wave particles move at medium speed in parallel to the direction that the wave moves
Hope this helps ^-^
Tension in the rope due to applied force will be given as
angle of applied force with horizontal is 37 degree
displacement along the floor = 6.1 m
so here we can use the formula of work done
now we can plug in all values above
So here work done to pull is given by 691.8 J
Answer:
i hope it will be useful for you
Explanation:
F=5.6×10^-10N
R=93cm=0.93m
let take m1 and m2 =m²
according to newton's law of universal gravitation
F=m1m2/r²
F=m²/r²
now we have to find masses
F×r²=m²
5.6×10^10N×0.93m=m²
5.208×10^-9=m²
taking square root on b.s
√5.208×10^-9=√m²
so the two masses are m1=7.2×10^-5
and m2=7.2×10^-5
Answer:
<em>Fx = 121.24lb</em>
<em>F = 140lb</em>
Explanation:
Since we are not given the angles subtended by the force, we can assume it to be 30 degrees.
The y component of the force expressed by the formula:
Fy = Fsintheta
Given the y-component of the force F to bee 70lb
70lb = Fsintheta
Get magnitude of the force
F = 70/sin theta
F = 70/sin 30
F = 70/0.5
F = 140lb
Get the x-component of the force
Fx = Fcos theta
Fx = 140cos 30
Fx = 140(0.8660)
Fx = 1,212.4lb
<em>Hence the x-component of the force sis 121.24lb</em>
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<em>Note that the angle used was assumed. Other values can as well be used</em>
