To solve this exercise it is necessary to apply the equations related to the magnetic moment, that is, the amount of force that an image can exert on the electric currents and the torque that a magnetic field exerts on them.
The diple moment associated with an iron bar is given by,

Where,
 Dipole momento associated with an Atom
 Dipole momento associated with an Atom 
N = Number of atoms
  y previously given in the problem and its value is 2.8*10^{-23}J/T
 y previously given in the problem and its value is 2.8*10^{-23}J/T


The number of the atoms N, can be calculated as,

Where
 Density
 Density
 Molar Mass
 Molar Mass
A = Area
L = Length
 Avogadro number
Avogadro number


Then applying the equation about the dipole moment associated with an iron bar we have,



PART B) With the dipole moment we can now calculate the Torque in the system, which is



<em>Note: The angle generated is perpendicular, so it takes 90 ° for the calculation made.</em>
 
        
             
        
        
        
They both make a thing go faster and slower but the relationship is force.
        
                    
             
        
        
        
Answer:
 189 m/s
Explanation:
The pilot will experience weightlessness when the centrifugal force, F equals his weight, W.
So, F = W
 mv²/r = mg
v² = gr
v = √gr where  v = velocity, g = acceleration due to gravity = 9.8 m/s² and r = radius of loop = 3.63 × 10³ m 
So, v = √gr 
v = √(9.8 m/s² × 3.63 × 10³ m) 
v = √(35.574 × 10³ m²/s²) 
v = √(3.5574 × 10⁴ m²/s²) 
v = 1.89 × 10² m/s
v = 189 m/s
 
        
             
        
        
        
The answer is true, is called Thermal pollotion:).