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3 years ago

Identify at least two ways that runoff can negatively impact an ecosystem.

1 answer:

Rudiy273 years ago

3 0

Technological systems are sets of interconnected components that transform, store, transport, or control materials, energy, and/or information for particular purposes. In any system, how the parts work together is as important as their individual characteristics.

Important technological systems concepts include:

input, output, transformation, and control"black box”redundancy and reliabilityoperational parameters.

System design, development, maintenance, and troubleshooting require the use of specialised language and representations.

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A hot-air balloon of diameter 12 mm rises vertically at a constant speed of 14 m/s. A passenger accidentally drops his camera fr

fgiga [73]

Answer:

The balloon is 66.62 m high

Explanation:

Combined Motion

The problem has a combination of constant-speed motion and vertical launch. The hot-air balloon is rising at a constant speed of 14 m/s. When the camera is dropped, it initially has the same speed as the balloon (vo=14 m/s). The camera has an upward movement for some time until it runs out of speed. Then, it falls to the ground. The height of an object that was launched from an initial height yo and speed vo is

$\displaystyle y=y_o+v_o\ t-\frac{g\ t^2}{2}$

The values are

$\displaystyle y_o=15\ m$

$\displaystyle v_o=14\ m/s$

We must find the values of t such that the height of the camera is 0 (when it hits the ground)

$\displaystyle y=0$

$\displaystyle y_o+v_o\ t-\frac{g\ t^2}{2}=0$

Multiplying by 2

$\displaystyle 2y_o+2v_ot-gt^2=0$

Clearing the coefficient of $t^2$

$\displaystyle t^2-\frac{2\ V_o}{g}\ t-\frac{2\ y_o}{g}=0$

Plugging in the given values, we reach to a second-degree equation

$\displaystyle t^2-2.857t-3.061=0$

The equation has two roots, but we only keep the positive root

$\displaystyle \boxed {t=3.69\ s}$

Once we know the time of flight of the camera, we use it to know the height of the balloon. The balloon has a constant speed vr and it already was 15 m high, thus the new height is

$\displaystyle Y_r=15+V_r.t$

$\displaystyle Y_r=15+14\times3.69$

$\displaystyle \boxed{Y_r=66.62\ m}$

3 0

3 years ago

A wire carries a current of 10 amps in a direction of 90 degrees with respect to the direction of an external magnetic field of

Oksi-84 [34.3K]

Answer:

15 N

Explanation:

The magnetic force on a piece of current-carrying wire is given by:

$F=ILB sin \theta$

where

I is the current in the wire

L is the length of the piece of wire

B is the magnetic field strength

$\theta$ is the angle between the direction of B and I

In this problem:

I = 10 A

B = 0.3 T

L = 5 m

$\theta=90^{\circ}$

Substituting into the equation, we find

$F=(10 A)(0.3 T)(5 m) sin 90^{\circ}=15 N$

6 0

3 years ago

An object with a mass of 5.0 kg accelerates 3.0 m/s2 after a force is applied to it. What is the amount

Studentka2010 [4]

Answer:

Dont

Explanation:

Know

8 0

2 years ago

8. As a roller coaster car crosses the top of a 51.0-m-diameter loop-the-loop, it's apparent weight is 1.80 times its true weigh

Vikki [24]

Answer:

The velocity at the top will be 26.4522 m/sec

Explanation:

We have given

The diameter of the loop d = 48.01 m

Radius of the loop $r=\frac{d}{2}=\frac{51}{2}=25.5m$

The apparent weight at the top is given by $\frac{mv^2}{r}-mg$

As the in question it is given that apparent weight is equal to 1.80 times of the real weight

$\frac{mv^2}{r}-mg=1.8mg$

$\frac{mv^2}{r}=2.8mg$

$v=\sqrt{2.8rg}=\sqrt{2.8\times 25.5\times 9.8}=26.4522m/sec$

So the velocity at the top will be 26.4522 m/sec

4 0

4 years ago

The ionization energy of an atom is the energy required to remove an electron from the atom. In the Bohr model, the ionization e

Aleksandr-060686 [28]

The question is incomplete, the complete question is;

The ionization energy of an atom is the energy required to remove an electron from the atom. In the Bohr model, the ionization energy equals the energy difference between the lowest energy level n = 1 , In which the electron is closest to the nucleus, and the energy level n oo, which has an infinite radius. Compared to the ionization energy of hydrogen, the energy required to remove the electron from singly ionized helium is O two times greater. O four times greater. eight times greater. O one-half as great. O one-fourth as great.

Answer:

four times greater

Explanation:

For a hydrogen atom, an ionization energy of 13.6 electron volts is required to eject its single electron from the lowest energy level all the way out of the atom.

The helium ground state contains only two 1s electrons. When one of these is removed, He^+ looks quite similar to H^+.

The energy required to remove the remaining helium electron should be; 4×(13.6eV)=54.4eV since the energy depends on the square of the nuclear charge.

7 0

3 years ago