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nekit [7.7K]
4 years ago
11

PLEASE HELP ME ASAP!!!!! MARK U AS BRAINLEST!

Physics
2 answers:
zmey [24]4 years ago
8 0
D) both air temperature and medium
LenKa [72]4 years ago
6 0

The speed of a sound wave depends on C) The air temperature

Hope I helped you :)

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An acetal polymer block is fixed to the rigid plates at its top and bottom surfaces. If the top plate displaces 2 mm horizontall
Taya2010 [7]

Answer:

The shear modulus of the polymer is 5 MPa

Solution:

As per the question:

displacement of the top plate, d = 2 mm = 0.002 m

Horizontal Force, P = 2 kN = 2000 N

Width of the block, w = 100 mm = 0.1 m

By small angle analysis:

Angle, \gamma = \frac{2}{200} = 0.01 rad

Now,

Stress, \tau = \frac{P}{Area} = \frac{2000}{0.4\times 0.1} = 50000 Pa

G = \frac{\tau}{\gamma} = \frac{50000}{0.01} = 5 MPa

3 0
3 years ago
A projectile is shot from the edge of a cliff h = 185 m above ground level with an initial speed of v0 = 145 m/s at an angle of
OleMash [197]
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4 years ago
Neutron stars have been overtaken by what
Bogdan [553]
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6 0
3 years ago
A 63-kg hiker is climbing the 828-m-tall Burj Khalifa in Dubai. If the efficiency of converting the energy content of the bars i
konstantin123 [22]

Answer:

T_f=5854.76 °C

Explanation:

Given:

mass of hiker, m= 63 kg

height to be climbed, h= 828 m

energy produced by an energy bar, E= 1.10\times 10^6 J

heat capacity of the hiker, c=75.3 J.mol^{-1}.K^{-1}= 4.184 J.kg^{-1}.K^{-1}

initial body temperature of hiker, T_i=36.6 \degree C

<em>The efficiency of converting the energy content of the bars into the work of climbing is 25%, the remaining 75% of the energy released through metabolism is heat released to her body.</em>

We find the energy required for climbing 828 m height:

W=m.g.h

W=63\times 9.8\times 828

W= 511207.2 J

∵Hike eats 2 energy bars= 2\times 1.1\times 10^{6} J

Energy produced= 2.2\times 10^{6} J

Now, according to her efficiency:

Total energy required for producing the work of W= 511207.2 J which is required to climb the given height will be (say, E):

25\% of E= 511207.2

\Rightarrow E= 511207.2\times \frac{100}{25}

E=2044828.8 J

&

Amount of total energy (E) converted into heat(Q) is:

Q=2044828.8-511207.2\\Q=1533621.6J

As we know that:

heat, Q=m.c. (T_f-T_i).................(1)

where:

T_f is the final temperature

Putting respective values in the eq. (1)

1533621.6= 63\times 4.184\times (T_f-36.6)

(T_f-36.6)\approx 5818.16

T_f\approx 5854.76 °C

4 0
3 years ago
The same type of engine is placed in iwo different airplanes The first airplane is twice as heavy as the second suchane Wrich
jeyben [28]

Answer:

i dont know this one

Explanation:

5 0
3 years ago
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