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Andrew [12]
3 years ago
7

Câu 1. Con lắc lò xo treo thẳng đứng, dao động điều hòa với biên độ 2cm và tần số góc 20 rad/s. Chiều dài tự nhiên của lò xo là

30cm. Chiều dài nhỏ nhất và lớn nhất của lò xo trong quá trình dao động là bao nhiêu? Lấy g = 10m/s2.
Physics
1 answer:
natka813 [3]3 years ago
8 0

Answer:

28 cm and 32 cm

Explanation:

1. The spring pendulum hangs vertically, oscillates harmonic with amplitude 2cm and angular frequency 20 rad/s. The natural length of

a spring is 30cm. What is the minimum and maximum length of the spring during the oscillation? Take g = 10m/s2.

As the amplitude is 2 cm and the natural length is 30 cm. So, it oscillates between 30 -2 = 28 cm to 30 + 2 = 32 cm.

So, the minimum length is 28 cm and the maximum length is 32 cm.

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How to do this question
Anna71 [15]

Answer:

(a) 10 m/s

(b) 22.4 m/s

Explanation:

(a) Draw a free body diagram of the car when it is at the top of the loop.  There are two forces: weight force mg pulling down, and normal force N pushing down.

Sum of forces in the centripetal direction (towards the center):

∑F = ma

mg + N = mv²/r

At minimum speed, the normal force is 0.

mg = mv²/r

g = v²/r

v = √(gr)

v = √(10 m/s² × 10.0 m)

v = 10 m/s

(b) Energy is conserved.

Initial kinetic energy + initial potential energy = final kinetic energy

½ mv₀² + mgh = ½ mv²

v₀² + 2gh = v²

(10 m/s)² + 2 (10 m/s²) (20.0 m) = v²

v = 22.4 m/s

4 0
3 years ago
A ball is thrown with a velocity of 10 m/s at a 25º from the horizontal. How far does the ball travel?
Stels [109]

Answer:

use a=v-u/t formula it will be correct

5 0
3 years ago
Assuming typical speeds of 8.5 km/s and 5.5 km/s for P and S waves, respectively, how far away did the earthquake occur if a par
taurus [48]

Answer:

The earthquake occurred at a distance of 1122 km

Explanation:

Given;

speed of the P wave, v₁ = 8.5 km/s

speed of the S wave, v₂ =  5.5 km/s

The distance traveled by both waves is the same and it is given as;

Δx = v₁t₁ = v₂t₂

let the time taken by the wave with greater speed = t₁

then, the time taken by the wave with smaller speed, t₂ = t₁ + 1.2 min, since it is slower.

v₁t₁ = v₂t₂

v₁t₁ = v₂(t₁ + 1.2 min)

v₁t₁ = v₂(t₁ + 72 s)

v₁t₁ = v₂t₁ + 72v₂

v₁t₁ - v₂t₁ = 72v₂

t₁(v₁ - v₂) = 72v₂

t_1 = \frac{72v_2}{v_1-v_2}\\\\t_1 =   \frac{72*5.5}{8.5-5.5}\\\\t_1 = 132 \ s

The distance traveled is given by;

Δx = v₁t₁

Δx = (8.5)(132)

Δx = 1122 km

Therefore, the earthquake occurred at a distance of 1122 km

4 0
3 years ago
For each of the following pairs of gas properties, describe the relationship between the properties, describe a simple system th
asambeis [7]

Answer:

For  each pair of properties of a gas, the relationships are (see the explanation for the description of the systems):

  1. (a) Volume and pressure: The relationship between them is inversely proportional.
  2. (b) Pressure and temperature: They have a directly proportional relationship.
  3. (c) Volume and temperature: They relationship is directly proportional.
  4. (d) Number of gas particles and pressure: The relationship is directly proportional between them.

Explanation:

1. Volume and pressure (temperature and amount of particles constant):

They have an inversely proportional relationship, because <em>if volume is reduced, the pressure increases, or if the volume increases, the pressure decreases</em>.

A simple system could be one similar to the one used by Boyle to test this relationship:

  • Seal the short extreme of a translucent J tube. It could be glass or plastic.
  • Put some water on it. As much as needed to have both sides of the tube filled.
  • Using a syringe, and a flexible small tube,inject a determined volume of air in the bottom in a way that the bubble is trapped in the seal side of the J tube.
  • Then if more water is added to the tube, it will increase the pressure (from the pressure definition is possible to in the trapped air, and is possible to measure the compression of the air bubble. The same is possible if using the syringe, and the flexible tube, some water is removed, and the increasing of volume could be observed.

2. Pressure and temperature (volume and amount of particles of the gas remains constant)

They have a directly proportional relationship, because <em>if temperature is reduced, the pressure decreases, or if the temperature increases, the pressure would increase, also</em>.

A simple system to show this is two cans of soda.

  • The can is rigid, so the volume is always constant, and the amount of gas inside the soda is the same.
  • Put one can under the sun, and the other in the cooler.
  • After a while, take it out the can in the cooler, and open both cans.
  • The one that was under the sun will "explode", in other words, it will liberate a lot of foam of gas and soda, meaning that the pressure inside the can was high.
  • The one that was in te cooler, won't liberate any foam, meaning that the pressure was low.

3. Volume and temperature (pressure and amount of particles of the gas remains constant)

They have a directly proportional relationship, because <em>if temperature is reduced, the pressure decreases, or if the temperature increases, the pressure will increase, also</em>.

A simple system to show this is a party balloon.

  • Fill the party balloon with some air, not enough to be close to explode, but enough to have it of a medium size. Tie the filling hole of the balloon.
  • The air inside the balloon would be at the same pressure than the atmosphere around it, so always will be at this pressure, and the close hole ensure that it has always the same amount of air inside.
  • Now is possible to use some heat source, for example as a hair dryer to increase the temperature of the balloon and its contents. The size of the balloon will increase. Then using water is possible to cool it down and watch how its size decreases.

4. Number of gas particles and pressure (volume and temperature of gas remains constant)

They have a directly proportional relationship, because <em>if the amount of gas particles is reduced, the pressure decreases, or if quantity of gas particles increases, the pressure will increase, also</em>.

A simple system to show this would be a bicycle tire:

  • The tire is rigid, so its volume is essentially constant, and the temperature would remains the same if not moving or driving it.
  • Using a tire gauge, it is possible to know the manometric pressure inside the tire, that is the difference between the actual pressure inside the tire and the atmospheric pressure.
  • Then each time that using an air pump some air is injected in the tire, it si possible to check the pressure inside it using the gauge, and observe how is increasing.
  • Also, is possible to open the valve, to allow some air to escape, then use the gauge to observe how the pressure decreases.

7 0
4 years ago
A physicist drives through a stop light. When he is pulled over, he tells the police officer that the Doppler shift made the red
Colt1911 [192]

Answer:

6.59\times 10^7m/s

Explanation:

We are given that

Wavelength of red light=\lambda=635nm

Wavelength of  green light=\lambda'=510 nm

We have to find the speed of physicist traveling according to his own testimony.

We know that

\frac{\lambda}{\lambda'}=\sqrt{\frac{1+\frac{v}{c}}{1-\frac{v}{c}}}

Where c=3\times 10^8m/s

Substitute the values

\frac{635}{510}=\sqrt{\frac{1+\frac{v}{c}}{1-\frac{v}{c}}}

1.25=\sqrt{\frac{1+\frac{v}{c}}{1-\frac{v}{c}}}

Squaring on both sides

1.5625=\frac{1+\frac{v}{c}}{1-\frac{v}{c}}

1.5625-1.5625\frac{v}{c}=1+\frac{v}{c}

1.5625-1=\frac{v}{c}+1.5625\frac{v}{c}=\frac{v}{c}(1+1.5625)

0.5625=2.5625\frac{v}{c}

v=\frac{0.5625c}{2.5625}=\frac{0.5625\times 3\times 10^8}{2.5625}

v=6.59\times 10^7m/s

8 0
3 years ago
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