Determine whether each equation is a linear equation. ... –2x – 3 = y .... linear. 16. 4y. 2. + 9 = –4. SOLUTION: Since y is squared, the equationcannot be written in standard form.
(2,-8) (3,-13) because if you plug them all in there the only ones that come out right
Since you need an isolated variable to use the substitution method, we need to re-arrange one of the equations. This will probably be easiest to do with the first one.
Add 5y to both sides of the first equation.
x=10+5y
Now, in the second equation, put in 10+5y in any spot that has an x.
2(10+5y)-10y=20
Distribute the 2 to both numbers in the parenthesis.
20+10y-10y=20
Combine like terms.
20=20
This means that the two equations are actually the same. You can see this if you multiply the whole first equation by 2
2(x-5y=10)
2x-10y=20, which is the same as the second equation. Therefore, the two equations are actually the same one.
You would pay $1100.15 (rounded to nearest hundredths)(unrounded would be 1100.14875)
