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4 years ago

Formula units in 0.0300 moles of cacl2

Chemistry

1 answer:

spin [16.1K]4 years ago

3 0

Answer:

no of formula unit = $0.03\times 6.023\times 10^{23}=1.8\times 10^{22}$

Explanation:

atomic mass of CaCl2 = 40 + 2×35.5 = 111 g.

no of formula unit = no of moles × Avagadro number

= $0.03\times 6.023\times 10^{23}=1.8\times 10^{22}$

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<h2>Answer:</h2>

We will need to know Avogadro's number and the molar mass of sucrose for this problem to do dimensional analysis.

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Molar mass of sucrose: 342.2965 g/mol

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4 years ago

A buffer solution is made up of acetic acid (CH3COOH) and sodium acetate (NaCH3COO). The major equilibria in the buffer system a

katrin [286]

The equilibria showing how the acetate buffer adjusts to addition of a small amount of NaOH is:

CH3COOH(aq) + H2O(1) → H30+ (aq) + CH3COO (aq)

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Buffers are made from solutions of weak acids and their salts or weak bases and their salts.

The equilibria showing how a buffer made from acetic acid and sodium acetate (NaCH3COO) adjusts to addition of a small amount of NaOH is as follows:

CH3COOH(aq) + H2O(1) → H30+ (aq) + CH3COO (aq)

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2 years ago

You find a little bit (0.150g) of a chemical marked Tri-Nitro-Toluene. Upon complete combustion in oxygen, you collect 0.204 g o

Elan Coil [88]

Answer:

The empirical formula is C7H5N3O6

Explanation:

Step 1: Data given

Mass of sample = 0.150 grams

Mass of CO2 = 0.204 grams

Molar mass CO2 = 44.01 g/mol

Mass of H2O = 0.030 grams

Molar mass H2O = 18.02 g/mol

Molar mass C = 12.01 g/mol

Molar mass H = 1.01 g/mol

Molar mass O = 16.0 g/mol

Step 2: Calculate moles CO2

Moles CO2 = mass CO2 / molar mass CO2

Moles CO2 = 0.204 grams / 44.01 g/mol

Moles CO2 = 0.00464 moles

Step 3: Calculate moles C

For 1 mol CO2 we have 1 mol C

For 0.00464 moles we have 0.00464 moles C

Step 4: Calculate mass C

Mass C = 0.00464 moles * 12.01 g/mol

Mass C = 0.0557 grams

Step 5: Calculate moles H2O

Moles H2O = 0.030 grams / 18.02 g/mol

Moles H2O = 0.00166 moles

Step 6: Calculate moles H

For 1 mol H2O we have 2 moles H

For 0.00166 moles H2O we have 2* 0.00166 = 0.00332 moles H

Step 7: Calculate mass H

Mass H = 0.00332 moles * 1.01 g/mol

Mass H = 0.00335 grams

Step 8: Calculate mass N

Mass N = 0.185 * 0.150 grams

Mass N = 0.02775 grams

Step 9: Calculate moles N

Moles N = 0.02775 grams / 14.0 g/mol

Moles N = 0.00198 moles

Step 10: Calculate mass O

Mass O = 0.150 grams - 0.02775 - 0.00335 - 0.0557

Mass O = 0.0632 grams

Step 11: Calculate moles O

Moles O = 0.0632 grams / 16.0 g/mol

Moles O = 0.00395 moles

Step 11: Calculate mol ratio

We divide by the smallest amount of moles

C: 0.00464 moles / 0.00198 moles =2.33

H: 0.00332 moles / 0.00198 moles = 1.66

N: 0.00198 moles / 0.00198 moles = 1

O: 0.00395 moles / 0.00198 moles = 2

For 1 mol N we have 2.33 moles C, 1.66 moles H and 2 moles O

For 3 moles N we have 7 moles C, 5 moles H and 6 moles O

The empirical formula is C7H5N3O6

5 0

3 years ago