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NeX [460]
3 years ago
13

Write a rule for the nth term of the sequence. Then find a20 37, 29, 21, 13,...

Mathematics
1 answer:
Pavlova-9 [17]3 years ago
7 0
The rule is –8

the 20th term would be -83
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If BE = 2x + 2, BD = 5x – 3, and AE = 4x – 6, what are the values of x and AC?
Keith_Richards [23]

Answer: x=7 and AC = 44 unuts.

Step-by-step explanation:

We know that the diagonals of a parallelogram bisect each other. (i)

Here in parallelogram ABCD , AC and Bd are diagonals intersecting at E.

BE = 2x + 2, BD = 5x – 3, and AE = 4x – 6

Using (i)

BE=\dfrac{BD}{2}\\\\2x+2=\dfrac{5x-3}{2}\\\\ 2(2x+2)=5x-3\\\\ 4x+4= 5x-3\\\\ 5x-4x=4+3\\\\ x= 7

Now , AE = 4(7)-6 = 28-6 = 22

AC =2 AE = 2 (22) =44 units.

Hence, x=7 and AC = 44 unuts.

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Decide which part of the quadratic formula tells you whether the quadratic equation can be solved by factoring:
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The part of the quadratic formula that dictates whether the function is factorable or not is B. b^2 - 4ac. This determines the number of real, imaginary, negative and positive roots. 
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