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Pavlova-9 [17]
3 years ago
5

a test has 20 multiple-choice questions with 5 choices each, followed by 35 true/false questions. if a student guesses on each q

uestion, how many ways can he answer the questions on the test
Mathematics
1 answer:
Nuetrik [128]3 years ago
3 0

Answer

There are 170 ways the student can answer the test.

Explanation

If there are 20 multiple-choice questions with 5 choices each, the student has 100 choices. The first question has 5 choices to pick from. The second has 5 as well. So does the third. Hopefully now you realize that you have to multiply the number of choices by the number of questions.

The same thing goes with the true/false questions. There are 2 choices for each true/false question, and there are 35 of those. 35×2 is 70. There are 70 ways to answer on the true/false questions.

Now combine the number of choices on the first part and the second part; 100+70 is 170.

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Fofino [41]

Answer: n=4,-4

Hope this helped

5 0
2 years ago
Read 2 more answers
Help !!! Brainlisest
AURORKA [14]

Answer:

(x, y ) → (x + 11, y - 11 )

Step-by-step explanation:

Consider the point U and its image U'

U (- 9, 1 ) → U' (2, - 10 )

This represents a shift of 2 - (- 9) = 2 + 9 = + 11 → in the x- direction and

- 10 - 1 = - 11 ↓ in the y- direction

This can be shown in the translation rule

(x, y ) → (x + 11, y - 11 )

7 0
3 years ago
Help with 5b please . thank you.​
Allushta [10]

Answer:

See explanation

Step-by-step explanation:

We are given f(x)=ln(1+x)-x+(1/2)x^2.

We are first ask to differentiate this.

We will need chain rule for first term and power rule for all three terms.

f'(x)=(1+x)'/(1+x)-(1)+(1/2)×2x

f'(x)=(0+1)/(1+x)-(1)+x

f'(x)=1/(1+x)-(1)+x

We are then ask to prove if x is positive then f is positive.

I'm thinking they want us to use the derivative part in our answer.

Let's look at the critical numbers.

f' is undefined at x=-1 and it also makes f undefined.

Let's see if we can find when expression is 0.

1/(1+x)-(1)+x=0

Find common denominator:

1/(1+x)-(1+x)/(1+x)+x(1+x)/(1+x)=0

(1-1-x+x+x^2)/(1+x)=0

A fraction can only be zero when it's numerator is.

Simplify numerator equal 0:

x^2=0

This happens at x=0.

This means the expression,f, is increasing or decreasing after x=0. Let's found out what's happening there. f'(1)=1/(1+1)-(1)+1=1/2 which means after x=0, f is increasing since f'>0 after x=0.

So we should see increasing values of f when we up the value for x after 0.

Plugging in 0 gives: f(0)=ln(1+0)-0+(1/2)0^2=0.

So any value f, after this x=0, should be higher than 0 since f(0)=0 and f' told us f in increasing after x equals 0.

8 0
2 years ago
Use properties of equality to simplify each of the following expressions so that you can simplify them in your head. Identify th
Salsk061 [2.6K]
Properties of equality have nothing to do with it. The associative and commutative properties of multiplication are used (along with the distributive property and the fact of arithmetic: 9 = 10 - 1).

All of these problems make use of the strategy, "look at what you have before you start work."


1. = (4·5)·(-3) = 20·(-3) = -60 . . . . if you know factors of 60, you can do this any way you like. It is convenient to ignore the sign until the final result.

2. = (2.25·4)·23 = 9·23 = 23·10 -23 = 230 -23 = 207 . . . . multiplication by 4 can clear the fraction in 2 1/4, so we choose to do that first. Multiplication by 9 can be done with a subtraction that is often easier than using ×9 facts.

4. = (2·5)·12·(-1) = 10·12·(-1) = (-1)·120 = -120 . . . . multiplying by 10 is about the easiest, so it is convenient to identify the factors of 10 and use them first. Again, it is convenient to ignore the sign until the end.

5. = 0 . . . . when a factor is zero, the product is zero
4 0
3 years ago
I need help...........​
bogdanovich [222]
Hello,

The answer is C, refer to this picture for an explanation.
Have a great day!!
Brainliest??

4 0
3 years ago
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