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Dafna11 [192]
3 years ago
10

PLZ HELP MARK BRAINLIEST 30 POINTS 1) Find the momentum of a 12 kg snowball that is rolling with a velocity of 9 m/s. 2) An 8 ba

ll with a mass of .5 kg is sitting at rest. It is hit by the cue ball (1 kg) traveling at 2.5 m/s. If the cue ball is at rest after the collision, how fast is the 8 ball traveling after the collision? 3) Two football players are running toward each other. If the offensive player is 75 kg and is running 8 m/s, how fast must the 60 kg defensive player run in order for the two players to hit and stop?
Chemistry
1 answer:
finlep [7]3 years ago
5 0

your probobility is equivilant to your

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Alpha helix and beta sheets are the secondary structure of protein
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You have 0.14 moles of sodium chloride (NaCl). How many grams do you have? ( 1 mole of NaCl = 58 grams NaCl) *
Step2247 [10]

Answer:

Option D is correct = 8.12 grams of NaCl

Explanation:

Given data:

Moles of sodium chloride = 0.14 mol

Mass of sodium chloride = ?

Solution:

Formula:

Number of moles = mass of NaCl / Molar mass of NaCl

Molar mass of NaCl = 58 g/mol

Now we will put the values in formula.

0.14 mol = Mass of NaCl / 58 g/mol

Mass of NaCl = 0.14 mol  ×  58 g/mol

Mass of NaCl = 8.12 g of NaCl

Thus, 0.14 moles of NaCl contain 8.12 g of NaCl.

4 0
3 years ago
The compound fes is an example of a(n) element ionic compound covalent compound atom
vfiekz [6]
FeS is an example of an ionic compound as in the formula there is a metal of Fe iron chemically bonded to the nonmetal S sulphur. Resulting in a strong electrostatic attraction due to the transfer of valence electrons from the iron to the Sulphur.
5 0
3 years ago
What is the pH if the [H+] is 10.25x10-7M?
Marysya12 [62]

Answer:

5.99

Explanation:

-log(10.25x10^-7)

- Hope this helps! Please let me know if you need further explanation.

7 0
3 years ago
Give me a hand,Solve this problem,Need everyone's help​
elixir [45]

Answer:

A. 8.8 g.

B. 5.3 g.

C. 449 g.

Explanation:

A. Determination of the mass of CO2.

Mole of CO2 = 0.2 mole

Molar mass of CO2 = 12 + (2×16)

= 12 + 32

= 44 g/mol

Mass of CO2 =?

Mole = mass /Molar mass

0.2 = mass of CO2 /44

Cross multiply

Mass of CO2 = 0.2 × 44

Mass of CO2 = 8.8 g

B. Determination of the mass of Na2CO3.

Mole of Na2CO3 = 0.05 mole

Molar mass of Na2CO3 = (2×23) + 12 + (3×16)

= 46 + 12 + 48

= 106 g/mol

Mass of Na2CO3 =?

Mole = mass /Molar mass

0.05 = mass of Na2CO3 /106

Cross multiply

Mass of Na2CO3 = 0.05 × 106

Mass of Na2CO3 = 5.3 g

C. Determination of the mass of Fe(OH)2.

Mole of Fe(OH)2 = 5 moles

Molar mass of Fe(OH)2 = 55.8 + 2(16 + 1)

= 55.8 + 2(17)

= 55.8 + 34

= 89.8 g/mol

Mass of Fe(OH)2 =?

Mole = mass /Molar mass

5 = mass of Fe(OH)2/89.8

Cross multiply

Mass of Fe(OH)2 = 5 × 89.9

Mass of Fe(OH)2 = 449 g.

8 0
3 years ago
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