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Dafna11 [192]
3 years ago
10

PLZ HELP MARK BRAINLIEST 30 POINTS 1) Find the momentum of a 12 kg snowball that is rolling with a velocity of 9 m/s. 2) An 8 ba

ll with a mass of .5 kg is sitting at rest. It is hit by the cue ball (1 kg) traveling at 2.5 m/s. If the cue ball is at rest after the collision, how fast is the 8 ball traveling after the collision? 3) Two football players are running toward each other. If the offensive player is 75 kg and is running 8 m/s, how fast must the 60 kg defensive player run in order for the two players to hit and stop?
Chemistry
1 answer:
finlep [7]3 years ago
5 0

your probobility is equivilant to your

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Find the percentage of mass in each of the element Ca ( HCO3)2 (Ca= 40, H = 1, O = 16, C= 35)​
Alex787 [66]

Answer:

% Ca = 24.69%

% H = 1.2%

% C = 14.8%

% O = 59.25%

Explanation:

The percentage by mass of each element can be calculated by dividing the mass of each element in the compound by the molar mass of the compound.

Molar mass of Ca(HCO3)2

Where; (Ca= 40, H = 1, O = 16, C= 12)

= 40 + {1 + 12 + 16(3)}2

= 40 + {13 + 48}2

= 40 + {61}2

= 40 + 122

= 162g/mol

- % mass of Ca = 40/162 × 100

= 0.2469 × 100

= 24.69%

- % mass of H = 2/162 × 100

= 0.012 × 100

= 1.2%

- % mass of C = 24/162 × 100

= 0.148 × 100

= 14.8%

- % mass of O = 96/162 × 100

= 0.5925 × 100

= 59.25%

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3 years ago
Which choice describes an organism found in the under story of a rain forest?
Sophie [7]

Answer:

Palms and other small trees

8 0
2 years ago
What is a controlled variable, a manipulated variable, and a responding variable in a science experiment??
ella [17]
A controlled variable is the one that is kept constant, the manipulated variable is the independent variable in an experiment , it is called manipulated because is the one that can be changed. A responding variable or variables are the dependent variables that change as a result of the changes in the manipulated variable.
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2 years ago
11. The back part of the cerebrum deals with hearing<br><br> True<br><br> False
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Answer:

The answer is: True

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2 years ago
The equilibrium: 2 NO2(g) \Longleftrightarrow&amp;iff; N2O4(g) has Kc = 4.7 at 100ºC. What is true about the rates of the forwar
Sergeeva-Olga [200]

Answer:

  • Initial: forward rate > reverse rate
  • Equilibrium: forward rate = reverse rate

Explanation:

2NO₂(g) → N₂O₄(g)   Kc=4.7

The definition of <em>equilibrium</em> is when the forward rate and the reverse rate are <em>equal</em>.

Because in the initial state there's only NO₂, there's no possibility for the reverse reaction (from N₂O₄ to NO₂). Thus the forward rate will be larger than the reverse rate.

7 0
2 years ago
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