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Andrei [34K]
3 years ago
8

A gas has a volume of 350.0 mL at 45.0°C. If the volume changes to 400.0 mL, what is the new

Chemistry
1 answer:
nekit [7.7K]3 years ago
5 0

Answer:

363.6 K

Explanation:

To solve this problem we will use Charles law equation i.e,

V1/T1 = V2/T2    

Given data

V1= 350 mL

T1= 45.0 °C

V2= 400.0 mL

T2=?

First of all we will convert the temperature into kelvin because the kelvin is an absolute scale of temperature.

T1= 45.0+ 273.15 = 318.15 K

Now we will put the values in equation

350 mL / 318 K = 400 mL / V2

V2= 400 mL × 318.15 K / 350 mL  

V2= 363.6 K

We can see that by increasing the temperature volume of given gas is also increases. we conclude that volume and temperature are directly proportional to each other. It is also confirmed by the Charles law.

“ The volume of given mass of a gas at a constant pressure is directly proportional to the absolute temperature ”

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Density = Mass / Volume
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The pressure changes from 2.13 atm to 1.80 atm.

Explanation:

Given data:

Initial pressure = ?

Final pressure = 1.80 atm

Initial temperature = 86.0°C (86.0 + 273 = 359 K)

Final temperature = 30.0°C (30+273 =303 K)

Solution:

According to Gay-Lussac Law,

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Mathematical relationship:

P₁/T₁ = P₂/T₂

Now we will put the values in formula:

P₁ = P₂T₁ /T₂

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P₁ = 646.2 atm. K /303 K

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if a sample of gas at 25.2 c has a volume of 536mL at 637 torr, what will its volume be if the pressure is increased to 712 torr
nignag [31]
Considering ideal gas:
PV= RTn

T= 25.2°C = 298.2 K

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:. n= (P1V1)/(RT) = ((0.8382 atm) x (0.536 L))/
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:. n= O.0184 mol

Then,
P2= 712 torr = 0.936842 atm

V2 = RTn/P2 = [(0.082atmL/
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