Answer:
Yes
Explanation:
A supercritical fluid has good properties for both liquid and as for extraction properties, the advantages then include:
- The fact that it has a lower viscosity than liquid CO2 allowing it to move through and around coffee beans more thoroughly with creating back pressure
- Its density is comparable to that of liquid CO2 meaning there is much CO2 per litre as there is liquid form making it more efficient
- It has a higher diffusivity than liquid CO2 which aids with penetration of the coffee beans on a molecular level
This experiment would not work with tea leaves because they also contain caffeine
Answer
a
Explanation:
the giraffe doesn't need carbon dioxide
This is the full question: what is the strongest intermolecular force in a liquid containing molecules with nonpolar bonds?
A. Covalent Bonds
B. Dispersion Forces
C. Hydrogen Bonds
D. none of these
This is the answer: B. Dispersion forces
Answer:
33.95 grams of NaN3
Explanation:
Number of moles of NaN3 = mass (m)/MW = m/65 mole
I mole of NaN3 requires 22.4L air bag
m/65 mole of NaN3 required 11.7L
22.4m/65 = 11.7
22.4m = 65×11.7
22.4m = 760.5
m = 760.5/22.4 = 33.95grams of NaN3
Answer:
ΔG = - 442.5 KJ/mol
Explanation:
Data Given
delta H = -472 kJ/mol
delta S = -108 J/mol K
So,
delta S = -0.108 J/mol K
delta Gº = ?
Solution:
The answer will be calculated by the following equation for the Gibbs free energy
G = H - TS
Where
G = Gibbs free energy
H = enthalpy of a system (heat
T = temperature
S = entropy
So the change in the Gibbs free energy at constant temperature can be written as
ΔG = ΔH - TΔS . . . . . . (1)
Where
ΔG = Change in Gibb’s free energy
ΔH = Change in enthalpy of a system
ΔS = Change in entropy
if system have standard temperature then
T = 273.15 K
Now,
put values in equation 1
ΔG = (-472 kJ/mol) - 273.15 K (-0.108 KJ/mol K)
ΔG = (-472 kJ/mol) - (-29.5 KJ/mol)
ΔG = -472 kJ/mol + 29.5 KJ/mol
ΔG = - 442.5 KJ/mol
