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2 years ago

If you evaporated 125 mL of a 3.5 M solution of iron(II) nitrite, how many moles of iron(II) nitrite would you recover?

Chemistry

1 answer:

Serhud [2]2 years ago

5 0

If 125 mL of a 3.5 M solution were evaporated, 0.438 moles of iron (II) nitrite would be recovered.

<h3>What is molarity?</h3>

Molarity is a measure of the concentration of a chemical species, in particular of a solute in a solution, in terms of moles of solute per liter of solution.

We want to find the moles of iron (II) nitrite (solute) in 125 mL of a 3.5 M solution. We will use the definition of molarity.

M = n / V(L)

n = M × V(L) = 3.5 mol/L × 0.125 L = 0.438 mol

where,

M is the molarity.
n is the number of moles.
V(L) is the volume of the solution in liters.

If 125 mL of a 3.5 M solution were evaporated, 0.438 moles of iron (II) nitrite would be recovered.

Learn more about molarity here: brainly.com/question/9118107

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The ksp of yttrium fluoride, yf3, is 8.62 × 10-21. calculate the molar solubility of this compound.

motikmotik

Answer:

The molar solubility of YF₃ is 4.23 × 10⁻⁶ M.

Explanation:

In order to calculate the molar solubility of YF₃ we will use an ICE chart. We identify 3 stages: Initial, Change and Equilibrium and we complete each row with the concentration of change of concentration. Let's consider the solubilization of YF₃.

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I 0 0

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