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Tems11 [23]
3 years ago
8

Consider some unknown compound containing only copper and oxygen. In order to determine the empirical formula, a sample of the c

ompound is decomposed into the elements copper and oxygen. The original sample had a mass of 0.6349g prior to decomposition. After the reaction, 0.5066g of pure copper solid was recovered. How many moles of copper were initially in the sample?
Chemistry
1 answer:
Lina20 [59]3 years ago
5 0

The number of mole of copper in the sample is 0.008 mole.

Mole is simply defined as the unit of amount in a substance.

The mole of a substance can be obtained by dividing the mass of the subtance by its molar mass i.e

Mole = mass / molar mass

With the above information, we can obtain the mole of copper in the compound as follow:

Mass of copper = 0.5066 g

Molar mass of copper = 63.5 g/mol

<h3>Mole of copper =? </h3>

Mole = mass / molar mass

Mole of copper = 0.5066 / 63.5

<h3>Mole of copper = 0.008 mole </h3>

Therefore, 0.008 mole of copper was initially present in the compound.

Learn more: brainly.com/question/14295066

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If a 100. -g sample of a hydrated compound contains 37.07-g sodium, 48.39-g carbonate and 14.54-g water, find the empirical form
Mumz [18]

he required empirical formula based on the data provided is Na2CO3.H2O.

<h3>What is empirical formula?</h3>

The term empirical formula refers to the formula of a compound which shows the ratio of each specie present.

We have the following;

Mass of sodium = 37.07-g

Mass of carbonate = 48.39 g

Mass of water = 14.54-g

Number of moles of sodium = 37.07-g/23 g/mol = 2 moles

Number of moles of carbonate = 48.39 g/61 g/mol = 1 mole

Number of moles of water = 14.54/18 g/mol = 1 mole

The mole ratio is 2 : 1: 1

Hence, the required empirical formula is Na2CO3.H2O

Learn more about empirical formula : brainly.com/question/11588623

3 0
2 years ago
The vapor pressure of water is 1.00 atm at 373 K, and the enthalpy of vaporization is 40.68 kJ mol!. Estimate the vapor pressure
Yuki888 [10]

Answer:

The vapor pressure at temperature 363 K is 0.6970 atm

The vapor pressure at 383 K is 1.410 atm

Explanation:

To calculate \Delta H_{vap} of the reaction, we use clausius claypron equation, which is:

\ln(\frac{P_2}{P_1})=\frac{\Delta H_{vap}}{R}[\frac{1}{T_1}-\frac{1}{T_2}]

where,

P_1 = vapor pressure at temperature T_1

P_2 = vapor pressure at temperature T_2

\Delta H_{vap} = Enthalpy of vaporization  

R = Gas constant = 8.314 J/mol K

1) \Delta H_{vap}=40.68 kJ/mol=40680 J/mol

T_1 = initial temperature =363 K

T_2 = final temperature =373 K

P_2=1 atm, P_1=?

Putting values in above equation, we get:

\ln(\frac{1 atm}{P_1})=\frac{40680 J/mol}{8.314J/mol.K}[\frac{1}{363}-\frac{1}{373}]

P_1=0.69671 atm \approx 0.6970 atm

The vapor pressure at temperature 363 K is 0.6970 atm

2) \Delta H_{vap}=40.68 kJ/mol=40680 J/mol

T_1 = initial temperature =373 K

T_2 = final temperature =383 K

P_1=1 atm, P_2?

Putting values in above equation, we get:

\ln(\frac{P_2}{1 atm})=\frac{40680 J/mol}{8.314J/mol.K}[\frac{1}{373}-\frac{1}{383}]

P_2=1.4084 atm \approx 1.410 atm

The vapor pressure at 383 K is 1.410 atm

8 0
3 years ago
You're invited to a hot tub party! Being the science geek that you are, you decide to calculate the amount of mL in the 650.0 ga
Sever21 [200]

Answer:

cool but can we have a little bit bigger

Explanation:

4 0
3 years ago
What's similar about the valence electrons of Carbon and Silicon?
Mars2501 [29]

Answer:

Explanation: Carbon and silicon BOTH come from Group 14 of the Periodic Table , i.e. both formally have the same number of valence electrons, 4 such electrons.........

5 0
2 years ago
Which group on the periodic table is the most reactive
Lostsunrise [7]

Answer:

Group 7 or the Halogens

Explanation:

The halogens occupies the 7th group on the periodic table. The group is made of F, Cl , Br, I and At.

The elements in this group are the most reactive of all elements. They are very reactive because they have just 7 electrons in their outermost shell and they only require an electron to complete their electronic configuration to produce an octet which typically mimics the stable group VIII elements.

This makes them very highly reactive.

7 0
3 years ago
Read 2 more answers
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