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Tems11 [23]
3 years ago
8

Consider some unknown compound containing only copper and oxygen. In order to determine the empirical formula, a sample of the c

ompound is decomposed into the elements copper and oxygen. The original sample had a mass of 0.6349g prior to decomposition. After the reaction, 0.5066g of pure copper solid was recovered. How many moles of copper were initially in the sample?
Chemistry
1 answer:
Lina20 [59]3 years ago
5 0

The number of mole of copper in the sample is 0.008 mole.

Mole is simply defined as the unit of amount in a substance.

The mole of a substance can be obtained by dividing the mass of the subtance by its molar mass i.e

Mole = mass / molar mass

With the above information, we can obtain the mole of copper in the compound as follow:

Mass of copper = 0.5066 g

Molar mass of copper = 63.5 g/mol

<h3>Mole of copper =? </h3>

Mole = mass / molar mass

Mole of copper = 0.5066 / 63.5

<h3>Mole of copper = 0.008 mole </h3>

Therefore, 0.008 mole of copper was initially present in the compound.

Learn more: brainly.com/question/14295066

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Consider the reaction between hydrogen gas and chlorine gas to form hydrogen chloride gas in a closed cylinder with a movable pi
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Answer:

In this case, the system doesn't be affected by the pressure change. This means that nothing will happen

Explanation:

We can answer this question applying the Le Chatelier's Principle. It says that changes on pressure, volume or temperature of an equilibrium reaction will change the reaction direction until it returns to the equilibrium condition again.

The results of these changes can define as:

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In the exercise, they mention a change on pressure of the system at constant temperature (that means the temperature doesn't change). As Le Chatelier Principle's says, we must analyze what happens if the pressure increase or decrease. If pressure increase the reaction will move on the side that have less quantity of moles, otherwise, if the pressure decreases the reaction will move to the side that have more quantity of moles. In this case, we can see that both sides of the equation have the same number of moles (2 for the reactants and 2 for the products). So, in this case, we can conclude that, despite the change on pressure (increase or decrease), nothing will happen.

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