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Tems11 [23]
3 years ago
8

Consider some unknown compound containing only copper and oxygen. In order to determine the empirical formula, a sample of the c

ompound is decomposed into the elements copper and oxygen. The original sample had a mass of 0.6349g prior to decomposition. After the reaction, 0.5066g of pure copper solid was recovered. How many moles of copper were initially in the sample?
Chemistry
1 answer:
Lina20 [59]3 years ago
5 0

The number of mole of copper in the sample is 0.008 mole.

Mole is simply defined as the unit of amount in a substance.

The mole of a substance can be obtained by dividing the mass of the subtance by its molar mass i.e

Mole = mass / molar mass

With the above information, we can obtain the mole of copper in the compound as follow:

Mass of copper = 0.5066 g

Molar mass of copper = 63.5 g/mol

<h3>Mole of copper =? </h3>

Mole = mass / molar mass

Mole of copper = 0.5066 / 63.5

<h3>Mole of copper = 0.008 mole </h3>

Therefore, 0.008 mole of copper was initially present in the compound.

Learn more: brainly.com/question/14295066

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If the gravitational force exists between all objects in the universe, why aren’t people affected by the gravitational force exe
AveGali [126]

Answer:

has a very small range

Explanation:

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8 0
2 years ago
.A gas occupies 25,3 mL at a pressure of 152 kPa. Find the volume if the pressure is
Strike441 [17]

Answer:

47.36mL

Explanation:

Using Boyles law equation, which states that:

P1V1 = P2V2

Where;

V1 = initial volume (mL)

V2 = final volume (mL)

P1 = initial pressure (atm)

P2 = final pressure (atm)

Based on the provided information, V1 = 25.3mL, P1 = 152 kPa, V2 = ?, P2 = 0.804atm

First, we need to convert 152kPa to atm by dividing by 101

1kPa = 0.0099atm

152kPa = 1.505atm

P1V1 = P2V2

1.505 × 25.3 = 0.804 × V2

38.08 = 0.804V2

V2 = 38.08/0.804

V2 = 47.36mL

5 0
3 years ago
How to calculate the percentage of a anhydrous salt
Anna35 [415]
Yep u right bro but like you know I’m here with these guys you know what I mean tho
8 0
3 years ago
Students in a chemistry class added 5 g of Zinc to 50 g of hydrochloric acid. A chemical reaction occurred that produced zinc ch
Vinil7 [7]

Answer:

Mass = 11 g

Explanation:

Given data:

Mass of Zn = 5 g

Mass of HCl = 50 g

Mass of hydrogen gas produced = 6 g

Mass of zinc chloride produced = ?

Solution:

Chemical equation:

Zn + 2HCl    →   ZnCl₂ + H₂

Number of moles of Zn:

Number of moles = mass / molar mass

Number of moles = 5 g / 65.38 g/mol

Number of moles = 0.08 mol

Number of moles of HCl :

Number of moles = mass / molar mass

Number of moles = 50 g / 36.5 g/mol

Number of moles = 1.4 mol

Now we will compare the moles of both reactant with zinc chloride.

              Zn           :           ZnCl₂

               1             :             1

              0.08       :        0.08

            HCl          :         ZnCl₂

              2            :           1

             1.4          :         1/2×1.4 =0.7 mol

The number of moles of zinc chloride produced by Zn are less so it will limiting reactant.

Mass of zinc chloride:

Mass = number of moles × molar mass

Mass = 0.08 mol × 136.3 g/mol

Mass = 11 g

5 0
3 years ago
4. Arrange the following substances in order of increasing boiling point: CH3CH2OH, HOCH2CH2OH, CH3CH2Cl , and ClCH2CH2OH A. CH3
Studentka2010 [4]

Answer: Option (B) is the correct answer.

Explanation:

A molecules that will have more number of hydrogen bonding will has highest boiling point because to break the hydrogen bonds high heat needs to be provided.

So, in the molecule HOCH_{2}CH_{2}OH there is presence of two alcoholic groups. Hence, it will have strongest hydrogen bonding as compared to the rest of molecules.

In the molecule ClCH_{2}CH_{2}OH there will be hydrogen bonding and dipole-dipole interactions. Hence, it boiling point will be slightly less than HOCH_{2}CH_{2}OH.

In the molecule CH_{3}CH_{2}OH, there will be only hydrogen bonding. Hence, its boiling point is less than ClCH_{2}CH_{2}OH.

In the molecule CH_{3}CH_{2}Cl, there is no hydrogen bonding but there will be only dipole-dipole interactions. Hence, its boiling point will be the least.

Therefore, we can conclude that increasing order of boiling point will be as follows.

        CH_{3}CH_{2}Cl < CH_{3}CH_{2}OH < ClCH_{2}CH_{2}OH < HOCH_{2}CH_{2}OH

6 0
3 years ago
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