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Tems11 [23]
3 years ago
8

Consider some unknown compound containing only copper and oxygen. In order to determine the empirical formula, a sample of the c

ompound is decomposed into the elements copper and oxygen. The original sample had a mass of 0.6349g prior to decomposition. After the reaction, 0.5066g of pure copper solid was recovered. How many moles of copper were initially in the sample?
Chemistry
1 answer:
Lina20 [59]3 years ago
5 0

The number of mole of copper in the sample is 0.008 mole.

Mole is simply defined as the unit of amount in a substance.

The mole of a substance can be obtained by dividing the mass of the subtance by its molar mass i.e

Mole = mass / molar mass

With the above information, we can obtain the mole of copper in the compound as follow:

Mass of copper = 0.5066 g

Molar mass of copper = 63.5 g/mol

<h3>Mole of copper =? </h3>

Mole = mass / molar mass

Mole of copper = 0.5066 / 63.5

<h3>Mole of copper = 0.008 mole </h3>

Therefore, 0.008 mole of copper was initially present in the compound.

Learn more: brainly.com/question/14295066

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Snezhnost [94]

Answer:

Pure Glycol

For example,

Antifreeze will freeze at minus 34 degrees.

Also prevents your car from freezing up because of the Pure Gycol in it.

6 0
3 years ago
If the density of nitrogen gas at a certain pressure and temperature is 1.20 g/L, how many moles of nitrogen gas are in 15.0 L.
Irina18 [472]
<h3>Answer:</h3>

0.643 moles

<h3>Explanation:</h3>

We are given;

Density of nitrogen gas as 1.20 g/L

Volume nitrogen as 15.0 L

We are required to calculate the number moles of nitrogen gas;

<h3>Step 1: Determine the mass of nitrogen gas</h3>

We know the density is given by dividing mass by volume.

  • Density = Mass ÷ volume

Therefore, to get the mass;

  • Mass = Density × volume
  • Mass = 1.20 g/L × 15.0 L

        = 18 g

<h3>Step 2: Determine the mass of nitrogen gas </h3>

We know that to get the number of moles, we divide mass by molar mass;

That is, moles = Mass ÷ Molar mass

But, molar mass of nitrogen gas is 28 g/mol

Therefore;

Moles of nitrogen gas = 18 g ÷ 28 g/mol

                                     = 0.643 moles

Therefore, the number of moles of nitrogen gas 0.643 moles

5 0
4 years ago
A major component of gasoline is octane when octane is burned in air it chemically reacts with oxygen to produce carbon dioxide
yan [13]

gasoline is the chemical that is coming out of the air

7 0
3 years ago
How many grams of NaCI are present in 11.00 moles
Amiraneli [1.4K]

Answer: 642.93 g of NaCl

Explanation:

11.00 mol NaCl  x  __58.448 g__  =  642.928 g of NaCl

                                 1 mol NaCl

I would round to 642.93 g of NaCl, but round to however many significant figures asked for.

My chemistry teacher made this map (image attached) to teach us how to do conversions. Just follow the map. I think it's pretty straight forward. I hope this helps.

7 0
3 years ago
What is the gravitational potential energy of a 5 kg object that is 150
marusya05 [52]

Explanation:

Gravitational potential energy

= mgh

= (5kg)(9.81N/kg)(150m)

= 7357.5J.

5 0
3 years ago
Read 2 more answers
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