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4 years ago

Evaluate \dfrac14c+3d 4 1 c+3d when c=6c=6 and d=7d=7.

Mathematics

1 answer:

Lubov Fominskaja [6]4 years ago

5 0

Answer:

The value of given expression is 22.5.

Step-by-step explanation:

The given expression is

$\frac{1}{4}c+3d$

Where, c=6 and d=7.

Substitute c=6 and d=7 in the given expression.

$\frac{1}{4}c+3d=\frac{1}{4}\times (6)+3\times (7)$

$\frac{1}{4}c+3d=\frac{3}{2}+21$

$\frac{1}{4}c+3d=\frac{3+42}{2}$

$\frac{1}{4}c+3d=\frac{45}{2}$

$\frac{1}{4}c+3d=22.5$

Therefore the value of given expression is 22.5.

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