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4 years ago

Evaluate \dfrac14c+3d 4 1 c+3d when c=6c=6 and d=7d=7.

Mathematics

1 answer:

Lubov Fominskaja [6]4 years ago

5 0

Answer:

The value of given expression is 22.5.

Step-by-step explanation:

The given expression is

$\frac{1}{4}c+3d$

Where, c=6 and d=7.

Substitute c=6 and d=7 in the given expression.

$\frac{1}{4}c+3d=\frac{1}{4}\times (6)+3\times (7)$

$\frac{1}{4}c+3d=\frac{3}{2}+21$

$\frac{1}{4}c+3d=\frac{3+42}{2}$

$\frac{1}{4}c+3d=\frac{45}{2}$

$\frac{1}{4}c+3d=22.5$

Therefore the value of given expression is 22.5.

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Answer:

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Read the explanation

Step-by-step explanation:

Rewrite this problem as a numerical expression. As per the wording of this problem, there can be two expressions derived.

1. $((\frac{1}{6}(10*3)*4)-30$

2. $30-((\frac{1}{6}(10*3)*4)$

Simplify, remember the order of operations. The order of operations is the sequence by which one is supposed to perform operations in a numerical expression. This order is the following:

1. Parenthesis

2. Exponents

3. Multiplication or division

4. Addition or Subtraction

Use this sequence when simplifying and solving the expression:

Expression 1

$((\frac{1}{6}(10*3)*4)-30\\\\=((\frac{1}{6}(30)*4)-30\\\\=(5*4)-30\\\\=20 - 30\\\\= -10$

Expression 2

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Evaluate \dfrac14c+3d 4 1 ​ c+3d when c=6c=6 and d=7d=7.

Evaluate \dfrac14c+3d 4 1 c+3d when c=6c=6 and d=7d=7.