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3 years ago

Which Best describes a characteristic of the jet stream?

Physics

1 answer:

Ipatiy [6.2K]3 years ago

7 0

Answer:

Im acually a pilot and i do not know this that well, but it was to do with the atmosphere

Explanation:

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A large block attached to a spring is undergoing simple harmonic motion horizontally, with angular frequency ω and amplitude A.

Naily [24]

Answer:

Explanation:

It is a problem based on simple harmonic motion and friction . maximum friction possible between large block and mass m is µ mg . During SHM , maximum acceleration is ω² A and force is mω² A .

friction must exceed it so that mass m may not slip over it during motion . so

µ mg ≥ mω² A

µ ≥ mω² A / mg

smallest value of µ

= mω² A / mg

= ω² A /g

3 0

4 years ago

What components make up fire

Tju [1.3M]

Answer:

Oxygen, heat, and fuel

Explanation:

7 0

3 years ago

A mass of a spring vibrates in simple harmonic motion at a frequency of 8.0 Hz and an amplitude of 3.9 cm. If a timer is started

oee [108]

Answer:

e = 50.27 give / s

Explanation:

The expression for simple harmonic motion is

x = A cos (wt + Ф)

in this case they give us the amplitude A = 3.9 cm and frequency f = 8.0 Hz

The angular and linФear variables are related

e = 2π d

e = 2π 8

e = 50.27 give / s

let's look for the constant fi

so let's find the time to have the maximum displacement

v = dx / dt

v = -A w sin (wt +Ф)

for the point of maximum displacement the speed is I think

0 = - sin (0 + Ф)

therefore fi = 0

Let's put together the equation of motion

x = 0.039 sin (50.27 t)

v = 0.039 50.27 sin (50.27 3)

v = 1.96 50 0.01355

v = 0.0266 m / s

8 0

3 years ago

The only force acting on a 3.2 kg canister that is moving in an xy plane has a magnitude of 6.7 N. The canister initially has a

Fynjy0 [20]

Answer:

The work done by the force is 5.76 J

Explanation:

Given;

mass of canister , m = 3.2 kg

magnitude of force, f = 6.7 N

initial velocity of the canister on x-axis, $v_i$ = 3.3i m/s

final velocity of the canister on y- axis, $v_f$ = 6.9j m/s

The work done on the canister = change in the kinetic energy of the canister

$W = K.E_f - K.E_i$

where;

K.Ei is the initial kinetic energy

K.Ef is the final kinetic energy

The initial kinetic energy:

$K.E_i = \frac{1}{2} *m\sqrt{i^2 +j^2+z^2}\\\\K.E_i = \frac{1}{2} *3.2\sqrt{3.3^2 +0^2+0^2}\\\\K.E_i = 5.28 \ J$

The final kinetic energy:

$K.E_f = \frac{1}{2} *m\sqrt{i^2 +j^2+z^2}\\\\K.E_f = \frac{1}{2} *3.2\sqrt{0^2 +6.9^2+0^2}\\\\K.E_f = 11.04 \ J\\$

W = 11.04 - 5.28

W = 5.76 J

Therefore, work done on the canister by the 6.7 N force during this time is 5.76 J

3 0

3 years ago

What answer is this? Pls help I’m freaking out

kolbaska11 [484]

Answer:

do u still need help it has been 2 weeks ??

Explanation:

8 0

3 years ago