Answer:
The coefficient of kinetic friction is 1.03
Explanation:
<u>Step 1:</u> Given data
⇒ mass of the block = 0.600 kg
⇒ elastic constant k = 20 N/m
⇒ The spring is compressed by 20.0 cm (=x) = 0.2 m
⇒ Once it loses contact with the spring, the block travels a distance 33 cm
<u>Step 2:</u> Calculate the potential energy
Ep = 1/2 * k * x²
Ep = 1/2 * 20N/m * (0.2m)²
Ep = 0.4 Nm
<u>Step 3:</u> Calculate the coefficient of kinetic friction
At the end of the movement Potential energy = work
W = Ep = 0.4Nm = µx * m * g* x
µx = Ep / (m*g*x)
µx = 2Nm / ( 0.6 kg * 9.81 m/s² * 0.33m)
µx = 1.03
The coefficient of kinetic friction is 1.03
Answer:
<h3>
a)</h3>
<u>=> R= 6 Ohms(Ω)</u>
<h3>b)</h3>
<em>these lights operate at the usual 240 volts direct from the main electricity supply. Therefore,</em>
<em>R and 100 can interchange places</em>
<u>=> R = 576 Ω</u>
<u></u>
By Ohm's Law:
=> 240 = I × 576
=>
=> I = 0.417 A
<h3 /><h3>c)</h3>
I don't know it's resistance,... so sorry
<h3>d)</h3>
The brightness of the bulb in series is <em><u>less than</u></em> when they're placed individually.
For bulbs in series their resistance gets added to form the equivalent resistance of the two bulbs.
Their resistances are nothing but mere numbers and the sum of two numbers(positive of course) is greater than the numbers.
So, the effective resistance of some bulbs in series <u>is more</u> than the individual resistance.
And
<em>Brightness, i. e., Power</em>
If resistance increases, Power decreases.
Here, the effective resistance was for sure larger, therefore resistance was increasing, hence power decreased taking brightness along with it.
Answer:35.2 ft
Explanation:
Given
height of stick =4 ft
shadow length =2.8 ft
Angle of elevation of sun is
let the height of tree be h
as will remain same thus
h=35.2 ft
If P = W/T, then Divide the number of work, 600, by the number of time, 3s.
600/3 = 200
Your answer is 200W.