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german
3 years ago
9

CAN SOMEONE PLS HELP? I SUCK AT MATH AND NEED HELP PLSSSSS

Mathematics
1 answer:
Murrr4er [49]3 years ago
5 0
The greatest common factor of 9, 21, and 45 is 3.
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Siri, who is not yet 22 years old, is five years older than Lily. Write and solve an
Zolol [24]

Answer:

22-5= L

L = 17

Step-by-step explanation:

8 0
2 years ago
Analyze Relationships Julio and Jake reading assignments the same day Jake is reading a 168-page book at a rate of 24 pages per
lukranit [14]
24×1 1/4 is 30
Jake reads 24 per day
24×5=121
168-121=47
Julio reads 30 per day
30×5=150
180-150=30
Jake will have 17 more pages left to read than Julio.
5 0
3 years ago
5) Vanessa and Javier each signed up for new gym memberships. Vanessa pays a monthly fee of $25 and
tamaranim1 [39]

Answer: 6.5 and 6

Step-by-step explanation:

3 0
2 years ago
Using interval notation, the domain off is [- 3, 5] and the domain of g is [- 2, 7] . On what domain is f defined
Scorpion4ik [409]

Note: I am assuming you mean ''on what domain is f+g is defined''.

Answer:

We conclude that

  • Dom(f+g) = [-2, 5]

Step-by-step explanation:

Given the domain of f

[-3, 5]

Given the domain of g

[-2, 7]

  • The domain of a composition f+g would include the intersection of both domains.

In other words, the domain of a composition f+g includes all the inputs of x-values that are in the domain of both functions i.e. f and g.

so

Domain of f = [-3, 5]

The x-values lie in the domain of f interval are:

x = -3, -2, 1, 0, 1, 2, 3, 4, 5

Domain of g = [-2, 7]

The x-values lie in the domain of g interval are:

x = -2, 1, 0, 1, 2, 3, 4, 5, 6, 7

Therefore, the common x-values in both f and g would be:

-2, 1, 0, 1, 2, 3, 4, 5

Thus, we conclude that

  • Dom(f+g) = [-2, 5]
3 0
3 years ago
Expand each expression
matrenka [14]

Answer:

Option B - \ln(\frac{4y^5}{x^2})=\ln 4+5\ln y-2\ln x

Step-by-step explanation:

Given : Expression \ln(\frac{4y^5}{x^2})

To find : Expand each expression ?

Solution :

Using logarithmic properties,

\ln (\frac{A}{B})=\frac{\ln A}{\ln B}=\ln A-\ln B

and \ln (AB)=\ln A+\ln B

Here, A=4y^5 and B=x^2

\ln(\frac{4y^5}{x^2})=\frac{\ln 4y^5}{\ln x^2}

\ln(\frac{4y^5}{x^2})=\ln 4y^5-\ln x^2

\ln(\frac{4y^5}{x^2})=\ln 4+\ln y^5-\ln x^2

Using logarithmic property, \logx^a=a\log x

\ln(\frac{4y^5}{x^2})=\ln 4+5\ln y-2\ln x

Therefore, option B is correct.

3 0
2 years ago
Read 2 more answers
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