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stira [4]
4 years ago
7

What is the sum of the geometric series: 3∑5(-2/3)^ii=0

Mathematics
1 answer:
marta [7]4 years ago
7 0
We use the law of the sum of the 3 first terms of the geometric sequence:
\sum_{i=0}^35\left(\dfrac{-2}{3}\right)^i=5\dfrac{1-\left(\dfrac{-2}{3}\right)^4}{1-\left(\dfrac{-2}{3}\right)}\\=5\dfrac{\left(\dfrac{3^4-2^4}{3^4}\right)}{\left(\dfrac{5}{3}\right)}\\=3\left(\dfrac{65}{81}\right)=\dfrac{65}{27}
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<h3>Working with the cost equation.</h3>

Here we know that the cost equation is:

c(x) = 10*x + 900.

First, we want to get the fixed cost, it is given by evaluating the function in x = 0.

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Solving for x₀ we get:

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R: c ∈ [900, 2400]

If you want to learn more about domain and range:

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