To determine the mass of gasoline in the the tank, we need data on the density of gasoline. We multiply this value to the capacity of the gasoline tank. We do as follows:
Mass = 13 gallons (0.0038 m^3 / 1 gallons) ( 732.22 kg/m^3 ) = 36.17 kg or 361771.67 g
36.17 kg ( 2.2 lb / 1 kg ) = 79.58 lb
Answer:
1. a = -10 m/s²
2. a = 1.8 × 10³ km/h²; s = 0.31 km
Explanation:
1.
Given:
Initial speed (u): 30 m/s
Final speed (v): 0 m/s (rest)
Time elapsed (t): 3.0 s
Asked:
Acceleration (a)
Solution:
We will use the following expression.
a = (v-u)/t = (0 m/s - 30 m/s)/3.0 s = -10 m/s²
Final Answer:
a = -10 m/s²
2.
Given:
Initial speed (u): 50 km/h
Final speed (v): 60 km/h
Time elapsed (t): 20 s
Asked:
(a) Acceleration (a)
(b) Distance traveled (s)
Solution:
(a) First, we will convert the time to hours.
20 s × 1 h/3600 s = 0.0056 h
Then, we will use the following expression.
a = (v-u)/t = (60 km/h - 50 km/h)/0.0056 h = 1.8 × 10³ km/h²
(b) We will use the following expression.
s = u × t + 1/2 × a × t²
s = 50 km/h × 0.0056 h + 1/2 × 1.8 × 10³ km/h² × (0.0056 h)² = 0.31 km
Final Answer:
a = 1.8 × 10³ km/h²
s = 0.31 km
The bowling ball have more gravitational potential energy as it sit on top of the building
<u>Explanation:</u>
The energy that is possessed by an object due to the position of that object in the field of gravity is called Gravitational potential energy . The object that is present in the place that is very closer to the Earth's surface has a constant gravitational potential energy. When an object is at certain height there is a necessity of force for lifting that object form that height.
This is applies to the gravitational potential energy also.When two objects are placed at different heights, the object that is placed at the greater height will have more potential energy. This is because, the force necessary to take the object from greater height will be more.
Answer:
T2 = 133.333°K
Explanation:
Using Combined Gas Laws:
(600 torr)(10L)/500°K = (200 torr)(8L)/x°K
Cross multiply:
x°K (600 torr)(10L) = 500°K(200 torr)(8L)
Divide:
x°K = (500°K(200 torr)(8L))/(600 torr)(10L)
x = 400/3°K or 133.333°K
Answer:
Solution: Since the atomic mass of silver (Ag) is 107.87 amu, one mole of silver has a mass o f 107.87 grams. Therefore, there is one mole of Ag per 107.87 grams of Ag
Explanation:
