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Nana76 [90]
3 years ago
10

How many grams of Cl are in 465g of CaCl2

Chemistry
2 answers:
Rama09 [41]3 years ago
6 0
2 ways to do this
a. find %Cl in CaCl2
2 x 35.45g/mole = 70.9g Cl
70.9g Cl / 110.9g/mole CaCl2 = 63.93% Cl in CaCl2
0.6963 x 145g = 92.7g = mass Cl

b. determine moles CaCl2 present then mass Cl
145g / 110.9g/mole = 1.31moles CaCl2 present
2moles Cl / 1mole CaCl2 x 1.31moles = 2.62moles Cl
2.62moles Cl x 35.45g/mole = 92.7g Cl
goblinko [34]3 years ago
6 0

Answer:

297.4332 grams of chlorine is present in 465 grams of calcium chloride.

Explanation:

Mass of calcium chloride = 465 g

Molar mass of calcium chloride = 111 g/mol

Moles of calcium chloride = \frac{465 g}{111 g/mol}=4.1892 mol

1 mol of calcium chloride has 2 moles of chlorine atoms.

Then 4.1892 moles of calcium chloride has:

2 \times 4.1892 mol=8.3784 mol of chlorine atoms

Mass of 8.3784 moles of chlorine atom:

8.3784 mol × 35.5 g/mol=297.4332 g

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Theoretical yield is the quantity of a product obtained from the complete conversion of the limiting reactant in a chemical reaction. It is the amount of product resulting from a perfect chemical reaction and thus not the same as the amount you'll actually get from a reaction.

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Why was the line of best fit method used to determine the experimental value of absolute zero?
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Answer:

<u><em></em></u>

  • <u><em>Because the x-intercet of the graph represents volume zero, which indicates the minimum possible temperature or absolute zero.</em></u>

Explanation:

Charle's Law for ideal gases states that, at constant pressure, the <em>temperature</em> and the <em>volume</em> of a sample of gas are protortional.

                       \dfrac{V}{T}=k\\\\V=kT

That means that the graph of the relationship between Temperature, in Kelivn, and Volume is a line, which passes through the origin.

When you work with Temperature in Celsius, and the temperature is placed on the x-axis, the line is shifted to the left  273.15ºC.

Meaning that the Volume at 273.15ºC is zero.

You cannot reach such low temperatures in an experiment, and also, volume zero is not real.

Nevertheless, you can draw the line of best fit and extend it until the x-axis (corresponding to a theoretical volume equal to zero), and read the corresponding temperature.

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3 years ago
The table below shows the electronegativity values of various elements on the periodic table. Electronegativities A partial peri
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Answer:

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If the enantiomeric excess of a mixture is 75%, what are the % compositions of the major and minor enantiomer?
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Let us say that R is the major enantiomer, while S is the minor enantiomer, therefore the formula for enantiomeric excess (ee) is:

ee = (R – S) * 100%

 

Let us further say that the fraction of R is x (R = x), and therefore fraction of S is 1 – x (S = 1 – x), therefore:

75 = (x – (1 – x)) * 100

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Summary of answers:

R = major enantiomer = 0.875 or 87.5%

<span>S = minor enantiomer = (1 – 0.875) = 0.125 or 12.5%</span>

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