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3 years ago

How many grams of Cl are in 465g of CaCl2

2 answers:

6 0

2 ways to do this
a. find %Cl in CaCl2
2 x 35.45g/mole = 70.9g Cl
70.9g Cl / 110.9g/mole CaCl2 = 63.93% Cl in CaCl2
0.6963 x 145g = 92.7g = mass Cl

b. determine moles CaCl2 present then mass Cl
145g / 110.9g/mole = 1.31moles CaCl2 present
2moles Cl / 1mole CaCl2 x 1.31moles = 2.62moles Cl
2.62moles Cl x 35.45g/mole = 92.7g Cl

goblinko [34]3 years ago

6 0

Answer:

297.4332 grams of chlorine is present in 465 grams of calcium chloride.

Explanation:

Mass of calcium chloride = 465 g

Molar mass of calcium chloride = 111 g/mol

Moles of calcium chloride = $\frac{465 g}{111 g/mol}=4.1892 mol$

1 mol of calcium chloride has 2 moles of chlorine atoms.

Then 4.1892 moles of calcium chloride has:

$2 \times 4.1892 mol=8.3784 mol$ of chlorine atoms

Mass of 8.3784 moles of chlorine atom:

8.3784 mol × 35.5 g/mol=297.4332 g

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