Answer:
CH₃CH₂-CH₂CH₃
Explanation:
When an alkene, R-CH=CH-R reacts with H₂ in a Pt catalyst, the analogue alkane, R-CH₂-CH₂-R, is produced (Hydrogenation of alkenes via Pt/Pd catalyst)
Thus, the reaction of CH₃CH=CHCH₃ with H₂ under a platinum catalyst produce:
<h3>CH₃CH₂-CH₂CH₃</h3>
The analogue alkane
Volume=Mass over density. V= 220/55. V=4cm^3
Answer:
46.839728 grams of water
Explanation:
1 mole is equal to 1 moles H2O, or 18.01528 grams
18.01528 times 2.6 = 46.839728
There are 46.839728 grams h20 in 2.60 mol of the compound
A b c d c would be your answer
Answer:
Explanation:
Step 1: Data given
The equilibrium constant, Kc, for the following reaction is 4.76 * 10^-4 at 431 K
The equilibrium concentration of Cl2(g) is 0.233 M
Step 2: The balanced equation
PCl5(g) ⇄ PCl3(g) + Cl2(g)
Step 3: The initial concentration
[PCl5]= Y M
[PCl] = 0M
[Cl2] = 0M
Step 4: Calculate the concentration at equilibrium
[PCl5] = Y + X M = Y - 0.233 M
[PCl]= XM = 0.233 M
[Cl2]= XM = 0.233 M
Step 5: Define Kc
Kc = [Cl2]* [PCl3] / [PCl5]
4.76 * 10^-4 = 0.233² / (Y -0.233)
0.000476 = 0.05429 / (Y - 0.233)
Y - 0.233 = 0.05429 / 0.000476
Y - 0.233 = 114.05 M
Y = 114.283 M = the initial concentration
The concentration of PCl5 at the equilibrium is 114.05 M