A)planets
b)the sun
c)moons
e)comets
f)asteroids
Answer:
-1.46 m/s^2
Explanation:
Write down what is given first:
v0 = 12 m/s
vf = 0 m/s
d = 45 m
We are trying to find acceleration, so we will use the equation vf^2 = v0^2 + 2ad
Plug in the values we have:
0^2 = 12^2 + (2 x 45 x a)
a = - 1.46 m/s^2
Note that this acceleration is negative because the body is slowing down, so the acceleration with be negative, because the change in velocity is negative.
Answer:
E = 5.5 10² N /C
Explanation:
For this exercise let's use Newton's second law
F = m a
the force is electric
F = q E
we substitute
q E = m a
E = 
(1)
the acceleration can be found with kinematics,
v = v₀ + a t
as the particle starts from rest v₀ = 0
a = v / t
a = 160 / 2.90
a = 55.17 m / s²
the relationship
q / m = 0.100 C / kg
m / q = 10 kg / C
we use equation 1
E = 10 55.17
E = 551.7 N / C
E = 5.517 10² N / C
ask for the result with two significant figures
E = 5.5 10² N /C
Answer= 12.5 km
0.5 km x km
_______=______
1 min 25 min
Cross multiply
1x=12.5
divide both sides by 1
x=12.5
You traveled 12.5 km
The force required to pull one of the microscope sliding at a constant speed of 0.28 m/s relative to the other is zero.
<h3>
Force required to pull one end at a constant speed</h3>
The force required to pull one of the microscope sliding at a constant speed of 0.28 m/s relative to the other is determined by applying Newton's second law of motion as shown below;
F = ma
where;
- m is mass
- a is acceleration
At a constant speed, the acceleration of the object will be zero.
F = m x 0
F = 0
Thus, the force required to pull one of the microscope sliding at a constant speed of 0.28 m/s relative to the other is zero.
Learn more about constant speed here: brainly.com/question/2681210
