Can you please help me with this test
2 answers:
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Answer:
w1 = 4.04 / √r
Explanation:
This exercise should be done using Newton's second law, where the centripetal month acceleration, write the equation for the vertical axis and the radius of rotation
Y Axis
fr - W = 0
fr = W
X axis (radial)
N = m
The equation for the force of friction is
fr = μ N
Let's replace
μ (m
) = mg
Centripetal acceleration is
= v² / r
v = wr
= w² r
μ w² r = g
w = √(g/μ r)
In order for the trip to be safe, people must not move, so the friction must be static, let's calculate the angular velocity for the extreme values of the friction increase
μ = 0.60
w1 = √ (9.8 / 0.6 r)
w1 = 4.04 / √r
μ = 1.0
w2 = √ (9.8 / 1 r)
w2 = 3.13 / √r
To finish the calculation you need the radius of the cylinder, but for the same radius the safe speed is w1